Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 3)
3.
What was the day of the week on 17th June, 1998?
Answer: Option
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 
1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
Discussion:
165 comments Page 16 of 17.
Saurabh said:
1 decade ago
Muthaiyan good way of explanation.
MaheshMydo said:
1 decade ago
How did you arrive at MONTH CODES?
Shweta said:
6 years ago
Thank you @Arya, @Inshan, @Nitesh.
(1)
Shanthi said:
3 years ago
You are right, thanks @Sri Harsha.
(4)
Ekowseegar said:
9 years ago
How do find the odd days in 1999?
Sound said:
6 years ago
Why do we take that 1600 and 300?
Shruthi said:
6 years ago
How we got 5*3? Please tell me.
Ritesh said:
1 decade ago
Why 400 years have 0 odd day?
Raju said:
10 years ago
How can calculate in a week?
C.Paththira Selvi said:
1 decade ago
How to calculate this sum?
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