Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 3)
3.
What was the day of the week on 17th June, 1998?
Answer: Option
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 
1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
Discussion:
165 comments Page 16 of 17.
Aishu said:
1 decade ago
How to find the month code rajesh ?
Nitin said:
1 decade ago
How can I find no leap year in 97 year.
Vaibhav said:
1 decade ago
Nice one rajesh.
Chetan said:
1 decade ago
I am not understand problem correctly. Please anybody explain me.
Praveen said:
1 decade ago
If 5 odd days for 100 years, then for 400 years it will be 5x4=20 means 20%7 = 6 odd days no...? bit confused about this calculation....anybody help me please..
Praveen said:
1 decade ago
Please tell me how 0 odd days for 400 years ?
Sandeep said:
1 decade ago
Mr. Rajesh how you know year code.
Rajesh said:
1 decade ago
17th june 1998
year 98+
year code 24+
month code 05+
day 17+
144%7
140+4
wednesday is the answer
year 98+
year code 24+
month code 05+
day 17+
144%7
140+4
wednesday is the answer
Sathi said:
1 decade ago
How to calculate odd days in a year ?
Dinesh said:
1 decade ago
What's odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 1
97 years has 24 leap years + 73 ordinary years.
Odd days in 300 years = (5 x 3) 1
97 years has 24 leap years + 73 ordinary years.
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