Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 14)
14.
January 1, 2008 is Tuesday. What day of the week lies on Jan 1, 2009?
Answer: Option
Explanation:
The year 2008 is a leap year. So, it has 2 odd days.
1st day of the year 2008 is Tuesday (Given)
So, 1st day of the year 2009 is 2 days beyond Tuesday.
Hence, it will be Thursday.
Discussion:
18 comments Page 2 of 2.
Matt said:
5 years ago
@Priyanka
Don't add 1st Jan 2008 in your calculation. (2nd Jan 2008 to 1st Jan 2009) in total 366 days, hence 2 odd days.
Don't add 1st Jan 2008 in your calculation. (2nd Jan 2008 to 1st Jan 2009) in total 366 days, hence 2 odd days.
Divya agrawal said:
5 years ago
Answer will be Wedesday.
(4)
Pema Yangdon said:
5 years ago
Right @Divya Agrawal.
I also got Wednesday as answer.
I also got Wednesday as answer.
(8)
Khader hussain sha said:
5 years ago
@All.
The question in 1 Jan 2008, we know that 2008 is a leap year, assume that if 2008 was an non-leap year then it.
Will have 365 days, so when you divide 365/7 = 1 odd day all right, the day will we Wednesday but as it is a leap year it has 366 days now 366/7 = 2 odd days, now add to the date of 1 Jan 2008 = Tuesday + 2 Thursday.
If the question was like 1 Jan 2008 in Tuesday then what is 1 Jan 2007, the answer would be Monday, as 2007 is the simple year.
The question in 1 Jan 2008, we know that 2008 is a leap year, assume that if 2008 was an non-leap year then it.
Will have 365 days, so when you divide 365/7 = 1 odd day all right, the day will we Wednesday but as it is a leap year it has 366 days now 366/7 = 2 odd days, now add to the date of 1 Jan 2008 = Tuesday + 2 Thursday.
If the question was like 1 Jan 2008 in Tuesday then what is 1 Jan 2007, the answer would be Monday, as 2007 is the simple year.
(2)
Shreya said:
4 years ago
the answer should be friday according to me because 2008 odd days are 2 and 1 of 1st jan 2009 so it should be 2+1=3 tues +3 i.e friday
(4)
Dawa Gyaltshen said:
3 years ago
09-last two digit of the given year.
09/4=2[quoteint].
1-date given.
0-number of month (JFM=033, AMJ=614, JAS =625 and OND= 035).
6-no.of year (1600-1699=6, 1700-1799=4, 1800-1899=2,1900-1999=0, and 2000-2099=6).
Sum of all=18.
Sum/7= 4(remainder).
4 = Thursday (0=Sunday......,.6 = saturday).
09/4=2[quoteint].
1-date given.
0-number of month (JFM=033, AMJ=614, JAS =625 and OND= 035).
6-no.of year (1600-1699=6, 1700-1799=4, 1800-1899=2,1900-1999=0, and 2000-2099=6).
Sum of all=18.
Sum/7= 4(remainder).
4 = Thursday (0=Sunday......,.6 = saturday).
(1)
D R Mishra said:
3 years ago
Yes, Thursday is the right Answer.
(3)
Chithra R said:
7 months ago
It should be 2 days after, then the answer is Thursday.
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