Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 15)
15.
January 1, 2007 was Monday. What day of the week lies on Jan. 1, 2008?
Answer: Option
Explanation:
The year 2007 is an ordinary year. So, it has 1 odd day.
1st day of the year 2007 was Monday.
1st day of the year 2008 will be 1 day beyond Monday.
Hence, it will be Tuesday.
Discussion:
45 comments Page 3 of 5.
Hassan Azizi said:
2 years ago
How it would be Tuesday?
Anyone, please explain to me.
Anyone, please explain to me.
Hita said:
1 year ago
Is it Tuesday or Wednesday?
Anyone, please explain the right answer clearly.
Anyone, please explain the right answer clearly.
Oji khalnayak said:
2 months ago
Option B is correct because.
Leap year 2008 was not considered because 1 January was taken.
So, add +1.
Leap year 2008 was not considered because 1 January was taken.
So, add +1.
Hari said:
1 decade ago
Since 2008 is a leap year we should not count 2 odd days because the year was not completed.
2007:1 odd day.
Monday + 1 odd day = Tuesday.
2007:1 odd day.
Monday + 1 odd day = Tuesday.
Jackie said:
1 decade ago
No it should be wednesday.
RAMKUMAR said:
1 decade ago
Two years are leap year continuosly then only it should be thurday other wise wednesday.
But leap year is onl;y divisible br 4 if it is not a century.
But leap year is onl;y divisible br 4 if it is not a century.
Sandy said:
1 decade ago
I want correct explanation please can any one help me.
Mary said:
1 decade ago
Two years cannot be leap years continously and the year which is divisible by 4 only is a leap year.
Pinto said:
1 decade ago
2008=1600+400+8
1600=0 odd day
400 = 0 odd days
8 =8/4=2 leap year + 6 ordinary year
=2*2=4 + 6*1 =10
10/7=3 (Wednesday)
1600=0 odd day
400 = 0 odd days
8 =8/4=2 leap year + 6 ordinary year
=2*2=4 + 6*1 =10
10/7=3 (Wednesday)
Kevin said:
1 decade ago
Since 2008 is a leap year. It has 2 odd days, so if January 1, 2007 was Monday, then Jan. 1, 2008 should be 2 days beyond Monday, which is Wednesday.
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