Aptitude - Boats and Streams - Discussion

Discussion Forum : Boats and Streams - General Questions (Q.No. 15)
15.
A man rows to a place 48 km distant and come back in 14 hours. He finds that he can row 4 km with the stream in the same time as 3 km against the stream. The rate of the stream is:
1 km/hr
1.5 km/hr
2 km/hr
2.5 km/hr
Answer: Option
Explanation:

Suppose he move 4 km downstream in x hours. Then,

Speed downstream = 4 km/hr.
x

Speed upstream = 3 km/hr.
x

48 + 48 = 14 or x = 1 .
(4/x) (3/x) 2

So, Speed downstream = 8 km/hr, Speed upstream = 6 km/hr.

Rate of the stream = 1 (8 - 6) km/hr = 1 km/hr.
2

Discussion:
48 comments Page 4 of 5.

Subhrasubha priyadarsini said:   8 years ago
4/x+y=3/x-y,
4x-4y=3x+,
x=7y -----> eq1
48/x+y +48/x-y =14,
48/8y+48/6y=14,
14/y=14,
y=1,
Now x=7.

Vicky said:   4 years ago
He finds that he can row 4 km with the stream in the same time as 3 km against the stream.
So,4 -3 = 1.
(8)

Aparna said:   1 decade ago
How did you got that x=12 I think x=7/14 so x=1/2?

Can you explain me is it right are wrong please?

Mandal shuvo said:   6 years ago
Let rate upstream be x and downstream be x/2 then required ratio be 3x/4:x/4 = 3 : 1 is answer.

Mahesh said:   1 decade ago
@Jain.

How come v = (48+48)/14 = 7.
The ans is 6.857.

Have you taken it approximately.

Anik said:   1 decade ago
@Rohit

It is impossible without assuming x i.e algebraic method, learn more on this.

Kajal said:   5 years ago
I'm not understanding this one I mean I don't get 1/2 by solving the equation.

Pulak sarkar said:   9 years ago
Downstream 4/x = 4/1/2 = 4*2 = 8kmph.

Upstream 3/x = 3/1/2 = 3*2 = 6kmph.

Rrr said:   4 years ago
@Raihan.

How do we solve those two equations? Please explain that too.
(3)

Jamshaid said:   3 years ago
How X/Y = 7?

By simplifying (X+Y) / (X-Y) = 4/3.

Please explain.
(3)


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