Aptitude - Boats and Streams - Discussion

Discussion Forum : Boats and Streams - General Questions (Q.No. 4)
4.
A motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream (in km/hr) is:
4
5
6
10
Answer: Option
Explanation:

Let the speed of the stream be x km/hr. Then,

Speed downstream = (15 + x) km/hr,

Speed upstream = (15 - x) km/hr.

30 + 30 = 4 1
(15 + x) (15 - x) 2

900 = 9
225 - x2 2

9x2 = 225

x2 = 25

x = 5 km/hr.

Video Explanation: https://youtu.be/lMFnNB3YQOo

Discussion:
65 comments Page 3 of 7.

Anjali said:   10 years ago
Please explain it in an easy way, which will be helpful for me.

Sneha said:   10 years ago
How you people got 9/2? Please explain that.

Roneet Jena said:   1 decade ago
[(450-30x)+(450+30x)]/(225-x^2) = [900/(225-x^2)].

Srinivas said:   9 years ago
Nice explanation @Seetha.

Krishna said:   9 years ago
The answer is 4 * 1/2 = 2.

How is it possible the answer is 9/2. If 4+1/2 then only answer is 9/2.

Rohit said:   9 years ago
How came 4(1/2)?

Praveenbehera said:   9 years ago
Good explanation @Seetha. Thanks.

Priya said:   9 years ago
The speed of the current is 5 then the speed of the boat in downstream =u+v =15+5 =20;.
The speed of the boat in upstream = u-v = 15-5 =10;.
Time =distance/speed.
4 1/2 = 30/20+30/10.
9/2=9/2.

Pawan thakur said:   8 years ago
Sneha just like that 4 hours 30 minutes.

Convert 30 minutes 30/60 you will get 1/2.
Now 4 hours 30 minutes = 4*1/2 you will get 9/2 in place of 30 minutes put 1/2.

Gourav Shervegar said:   8 years ago
Why the speed of upstream is 15-x and speed of downstream is 15+x?


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