Aptitude - Boats and Streams - Discussion

Discussion Forum : Boats and Streams - General Questions (Q.No. 10)
10.
A boat covers a certain distance downstream in 1 hour, while it comes back in 1 hours. If the speed of the stream be 3 kmph, what is the speed of the boat in still water?
12 kmph
13 kmph
14 kmph
15 kmph
None of these
Answer: Option
Explanation:

Let the speed of the boat in still water be x kmph. Then,

Speed downstream = (x + 3) kmph,

Speed upstream = (x - 3) kmph.

(x + 3) x 1 = (x - 3) x 3
2

2x + 6 = 3x - 9

x = 15 kmph.

Discussion:
20 comments Page 1 of 2.

Priya said:   8 months ago
The ratio between time in downstream to upstream is 1:3/2 = 2:3, then the ratio between speed is 2 : 3(directly proportional).
The difference between the ratio is 1 and is given as 3.
The speed of still water is x+y that is (2+3)×3 = 15.

VYSHU said:   3 years ago
@All.

By checking the options we can find the answer.

Time has already been given in the question. And these options are the speed of the boat in still water.

And you know the rate of current as well. Just check which option gives you the same distance upstream as well as downstream (D=S*T).
(1)

Hardik raj said:   3 years ago
Why we have not taken total time as 5/2? Please explain it.

Ketan said:   5 years ago
If Time=Distance/Speed.

Speed=Distance*Time.

According to condition distance of D.S and U.S is same.
D.S=U.S.
(x+3)*1=(x-3)*3/2 {Remember S=D*T.}.
{i.e D.S and U.S distance which is x+3 and x-3 respectively} and {D.S and U.S time which is 1 and 1*1/2=3/2 respectively}

2x+6=3x-9 (Multiply both equations by 2 to get rid of denominator 2 and solve).
6+9=3x-2x.
x=15.
(1)

Mahek said:   6 years ago
I have one more way to solve it...

The boat goes downstream in 1 hour and returns back in 3/2 hours so we can conclude the boat covered the same distance.

Now, Sb = 1/2(Sd+Su)
Sb = 1/2(D/1 +D*2/3). As speed = Dist./Time
Sb = D(1/2+1/3)
Sb = D((5/6) -------> (1)

Also, Ss = 1/2(Sd-Su)
Ss = 1/2(D/1-D*2/3)
Ss = D(1/2-1/3)
Ss = D(1/6) -------> (2)

Now if we take ratio of (1) & (2) then,
Sb/Ss = [D(5/6)]/[D(1/6)].
Sb/3 = 5.
As speed of stream is 3kmph.
Sb = 15 kmph.

Here Sb is the speed of the boat.
Ss is the speed of the stream.
Sd is the speed of downstream.
Su is the speed of upstream.
D is distance.

Kousalya said:   6 years ago
Yes, you are right. @Syed.

But we find only the distance. But the question asked is the speed of the boat in still water.

Can anyone explain this?
(1)

Dushyant Singh said:   7 years ago
Yes, right @Suraj Dev.

Natraj said:   7 years ago
The speed of the boat in still water formula is 1/2(a-b) right then why there is no usage of formula here.
(1)

Swapnagolla said:   7 years ago
Why we taken x-3 why can't 3-x?

Please explain me.
(1)

MZA said:   8 years ago
But in question, there is still water mention not, the velocity of the boat in "still water" needs to be found not in downstream.


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