Aptitude - Boats and Streams - Discussion

Discussion Forum : Boats and Streams - General Questions (Q.No. 9)
9.
A man can row at 5 kmph in still water. If the velocity of current is 1 kmph and it takes him 1 hour to row to a place and come back, how far is the place?
2.4 km
2.5 km
3 km
3.6 km
Answer: Option
Explanation:

Speed downstream = (5 + 1) kmph = 6 kmph.

Speed upstream = (5 - 1) kmph = 4 kmph.

Let the required distance be x km.

Then, x + x = 1
6 4

2x + 3x = 12

5x = 12

x = 2.4 km.

Discussion:
21 comments Page 1 of 3.

Anil said:   1 decade ago
2x+3x=12

Is that multiplication of 2*3.

If yes, why we have to multiply 2*3 ?

Sasikumar said:   1 decade ago
Speed downstream = (5 + 1) kmph = 6 kmph.

Speed upstream = (5 - 1) kmph = 4 kmph.

average speed=2(6)(4)/(6+4)

Bhima God said:   1 decade ago
Mul of 6 and 4 should be 24 right?...how that 12 comes?

Dts said:   1 decade ago
Here we take lcm only.

Rakesh KIIT said:   1 decade ago
Average Speed during toatal journey=2(6)(4)/(6+4)
=4.8 kmph
so, Total distance coverd during the Journey=Time* Average speed
=1*4.8
=4.8km
so, How far is the place = 4.8/2
= 2.4 km

Because man goes and come back.

Shantanu datta said:   1 decade ago
From where is this 12 coming from?

2x+3x=6 after the first step.

Kandarp Singh said:   1 decade ago
12 is the lcm of 4 and 6 and that expression solving is correct.

x/6 + x/4 = 1.

(4x+6x)/(6*4) = 1.

(2x+2x)/(3*4) = 1.

2x+3x = 12.

Ashwin Hingole said:   1 decade ago
I think answer to how far is the place should be 1.2 km. And answer to how much distance man has covered should be 2.4 km. He goes and comes back. Suggestions please.

Sam said:   1 decade ago
(4x+6x)/(6*4) = 1.
4x+6x = 24.

10x = 24.
x = 24/10.
x = 2.4.

I hope You are all understand.
(1)

Utteya Pal said:   10 years ago
Easiest way to do this kind of problems:

{z(x^2-y^2)}/2x.

Here z= time taken to cover the both distance.

x = speed in still water.

y = speed of current.


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