Aptitude - Boats and Streams - Discussion
Discussion Forum : Boats and Streams - General Questions (Q.No. 14)
14.
A man takes twice as long to row a distance against the stream as to row the same distance in favour of the stream. The ratio of the speed of the boat (in still water) and the stream is:
Answer: Option
Explanation:
Let man's rate upstream be x kmph.
Then, his rate downstream = 2x kmph.
![]() |
![]() |
2x + x | ![]() |
: | ![]() |
2x - x | ![]() |
2 | 2 |
= | 3x | : | x |
2 | 2 |
= 3 : 1.
Discussion:
30 comments Page 3 of 3.
Manoj said:
7 years ago
The distance is same so,
D/t = x.
where x is the speed of the boat in downstream.
D/t = 2x in upstream case.
D/t = x.
where x is the speed of the boat in downstream.
D/t = 2x in upstream case.
Amit 7677 said:
1 decade ago
Speed should be greater than x but less than 2x.hence mean is taken of 2x and x i.e. 2x+x/2
Einstein said:
8 years ago
How you relate the speed of the man with speed of the boat? Explain it.
Swetha reddy said:
6 years ago
How the speed of the boat in still water is (2x+x) /2?
Rajendra said:
1 decade ago
Can u explain how the below expression frames
2x+x/2
2x+x/2
Jamshaid said:
3 years ago
Here, the shortest way is
2(A-B) = A+B.
A/B = 3/1.
2(A-B) = A+B.
A/B = 3/1.
(8)
Ani said:
1 decade ago
Why should it be greater than x but lessthan 2x?
Vikas said:
2 decades ago
How speed of boat in still water is (2x+x) /2 ?
Rahulj said:
9 years ago
@Niklu Rana, your explanation is very nice.
Nithya said:
9 years ago
Thank you all for explaining the solution.
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