Aptitude - Average - Discussion

Oral solution: Total 55. As they moved out of group remaining elements have given 1 each, means these two have donated 9 in the group. So these two remained with 46.

Average is 23, so initial average is 23.

Is any body tell me that why we are reducing 1 from average age of 9 persons (x/9-1) ?

In above equation why we reducing that one?

Friends anybody solve this questions in a detailed manner.

Please explain this sum easily.

Please explain anybody in details.

I don't understand this problem please explain in details.

According to formula: Sum of people/Total number of people = Average

Assume:

Sum of people = W.

Total number of people = 11------given.

Average = X.
W/11 = X.

W = 11X --Since we need average not weight.

NOW it is said that exclude the weight of captain (26) and keeper (Since 3 year elder his age become 29). So that average become less than one year.

W-(26+29)/9 = X-1------(2)

Since two people have been excluded number of people remain 9.

Put equation 1 in equation 2.

= 11X-55 = 9(X-1).

2X = 55-9.
2X = 46.
X = 23.

So the average age after two people excluded is 23.

Hope you understand guys. Thank you.

Assume average of 11 people = x.

Total age/11 = x.

So total age = 11 x.

Then, One person age given i.e. 26 year.

Keeper is 3 year older so, 26+3 = 29 year.

By excluding the age of both person average become less than one year. i.e x-1.

Then total people is, 11-2 = 9.

Total age of both person = 26+29 = 55 years.

Total age of 9 people = 11x-55.

11x-55/9 = x-1.

11x-55 = 9x-9.

2x = 46.

x = 23.

So the average age of team is 23 year.

Can't we solve this numerical by, Alligation method?

Total 11 members.

So, 10 * 26 + 29 * 1/11 = 26.3.

If two are excluded,

8 * 26 + 29 * 1/11 = 21.6.

Average of team = 26.3 + 21.6/2.

So, the Answer is 23.