Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 6)
6.
The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?
Answer: Option
Explanation:
Let the average age of the whole team by x years.
11x - (26 + 29) = 9(x -1)
11x - 9x = 46
2x = 46
x = 23.
So, average age of the team is 23 years.
Discussion:
129 comments Page 6 of 13.
JAY DOSHI said:
10 years ago
Please explain this sum easily.
Jay doshi said:
10 years ago
Please explain anybody in details.
Rajeshri said:
10 years ago
I don't understand this problem please explain in details.
APARICHITH said:
10 years ago
According to formula: Sum of people/Total number of people = Average
Assume:
Sum of people = W.
Total number of people = 11------given.
Average = X.
W/11 = X.
W = 11X --Since we need average not weight.
NOW it is said that exclude the weight of captain (26) and keeper (Since 3 year elder his age become 29). So that average become less than one year.
W-(26+29)/9 = X-1------(2)
Since two people have been excluded number of people remain 9.
Put equation 1 in equation 2.
= 11X-55 = 9(X-1).
2X = 55-9.
2X = 46.
X = 23.
So the average age after two people excluded is 23.
Hope you understand guys. Thank you.
Assume:
Sum of people = W.
Total number of people = 11------given.
Average = X.
W/11 = X.
W = 11X --Since we need average not weight.
NOW it is said that exclude the weight of captain (26) and keeper (Since 3 year elder his age become 29). So that average become less than one year.
W-(26+29)/9 = X-1------(2)
Since two people have been excluded number of people remain 9.
Put equation 1 in equation 2.
= 11X-55 = 9(X-1).
2X = 55-9.
2X = 46.
X = 23.
So the average age after two people excluded is 23.
Hope you understand guys. Thank you.
Rutika said:
10 years ago
Assume average of 11 people = x.
Total age/11 = x.
So total age = 11 x.
Then, One person age given i.e. 26 year.
Keeper is 3 year older so, 26+3 = 29 year.
By excluding the age of both person average become less than one year. i.e x-1.
Then total people is, 11-2 = 9.
Total age of both person = 26+29 = 55 years.
Total age of 9 people = 11x-55.
11x-55/9 = x-1.
11x-55 = 9x-9.
2x = 46.
x = 23.
So the average age of team is 23 year.
Total age/11 = x.
So total age = 11 x.
Then, One person age given i.e. 26 year.
Keeper is 3 year older so, 26+3 = 29 year.
By excluding the age of both person average become less than one year. i.e x-1.
Then total people is, 11-2 = 9.
Total age of both person = 26+29 = 55 years.
Total age of 9 people = 11x-55.
11x-55/9 = x-1.
11x-55 = 9x-9.
2x = 46.
x = 23.
So the average age of team is 23 year.
Shubham LN said:
9 years ago
Can't we solve this numerical by, Alligation method?
Mounika Reddy said:
9 years ago
Total 11 members.
So, 10 * 26 + 29 * 1/11 = 26.3.
If two are excluded,
8 * 26 + 29 * 1/11 = 21.6.
Average of team = 26.3 + 21.6/2.
So, the Answer is 23.
So, 10 * 26 + 29 * 1/11 = 26.3.
If two are excluded,
8 * 26 + 29 * 1/11 = 21.6.
Average of team = 26.3 + 21.6/2.
So, the Answer is 23.
Vishal said:
9 years ago
For the answer to question how 9 (x-1) came?
Let x be the Avg of the whole team5.
(sum of the ages of all players) / (no. Of players) = Avg.
=>sum/11 = x.
=>sum =11x ------> (1 equation).
Similarly, Avg of 9 players is less than Avg of a team.
(sum of ages of 9 players) / (no. Of players) = x - 1.
=> (sum of ages of 9 players) /9 = x - 1.
=> (sum of ages of 9 players) =9 (x - 1) ---------> 2nd equation.
(sum of ages of 9 players) = (sum of ages of 11 players) - (captain and keepers age).
Now from eqn 1.
=> (sum of ages of 9 players) =11x - (26 + 29).
Put this in eqn 2.
11x - (26 + 29) = 9 (x - 1).
This answer can't be made more simple,
Let x be the Avg of the whole team
(sum of the ages of all players) / (no. Of players) = Avg.
=>sum/11 = x.
=>sum =11x ------> (1 equation).
Similarly, Avg of 9 players is less than Avg of a team.
(sum of ages of 9 players) / (no. Of players) = x - 1.
=> (sum of ages of 9 players) /9 = x - 1.
=> (sum of ages of 9 players) =9 (x - 1) ---------> 2nd equation.
(sum of ages of 9 players) = (sum of ages of 11 players) - (captain and keepers age).
Now from eqn 1.
=> (sum of ages of 9 players) =11x - (26 + 29).
Put this in eqn 2.
11x - (26 + 29) = 9 (x - 1).
This answer can't be made more simple,
Afzal said:
9 years ago
Total ageaof of 11 player ages 26 = 26 * 11 = 286.
Total of 11 player whose age 29 = 29 * 11 = 319 Difference = 33 average 1 less,
33 - 10 = 23.
Total of 11 player whose age 29 = 29 * 11 = 319 Difference = 33 average 1 less,
33 - 10 = 23.
Sam said:
9 years ago
I can't understand the question please help anyone.
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