Aptitude - Average - Discussion

Age of the captain of 11 members is 26 and the age of the wicket keeper is 4 year so how 26+29? Please anyone explain me.

The age of captain is 26 and wc age is more than 3.
So 29,
26 + 29 = 55,
55 - 9(team average is less one ) = 46,
And 46/2 = 23.

Cross check the answers:

X = 253/11 = 23,
X = 253 - 26 - 29 = 198,
198/9 = 22.

Let x be average of 11 people or team.

Total age of two-person is 26 + 29 = 55.
Total age of 11 people be= 11 * x = 11x.
It says when 2 people excluded avg is decreased by 1 so, it is = x - 1.
Now find the avg of 9 members.

{11x(total age) - 55( two person)}/9 = X-1.
So, 11x-55 = 9(x-1) "take 9 to other side".
Then solve it.

(X-1)? came? Please anyone explain me.

Thanks all for explaining it.

Let Avg age of dull team be x.

So acc to formula sum/n=avg----> equation 1)
We have 26+29+ 9 members of cricket team / 11 = x ---> equation 2)

Now Acc to ques: the average age of the remaining players is one year less than the average age of the whole team if those two players are excluded so again putting in eq 1,

9 members / 9 = x- 1 ----> equation 3.

where x is avg of the whole team

Get the value of 9 members from equation 2 and place it in eq 3.
We will get the answer as 23.

Thanks all for explaining the answer.

Captain age is =26,
Wicketkeeper age is 3 years older than captain that is =26+3=29,
Average of whole team=((Y+26+29)/11)=X,
X=average of the whole team,
Y =total age of remaining 9 members.
Total age of the whole team,
=(Y+26+29)=11X ---> Eq1.

2part
Two are excluded.
So remaining people are 9.
Average of remaining is 1 year less than the whole team,
That is =X-1,
Average of 9 members =(X-1)*Y/9,
Total age of 9 members =Y=9*(X-1) ---> Eq2.

Substitute eq2 in eq 1.
26+29+9X-9 = 11X,
46 = 2X,
X = 23.

Why 9(x-1) Instead of 9x-1? Please explain.