Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 7)
7.
The average monthly income of P and Q is Rs. 5050. The average monthly income of Q and R is Rs. 6250 and the average monthly income of P and R is Rs. 5200. The monthly income of P is:
Answer: Option
Explanation:
Let P, Q and R represent their respective monthly incomes. Then, we have:
P + Q = (5050 x 2) = 10100 .... (i)
Q + R = (6250 x 2) = 12500 .... (ii)
P + R = (5200 x 2) = 10400 .... (iii)
Adding (i), (ii) and (iii), we get: 2(P + Q + R) = 33000 or P + Q + R = 16500 .... (iv)
Subtracting (ii) from (iv), we get P = 4000.
P's monthly income = Rs. 4000.
Discussion:
93 comments Page 3 of 10.
Mani.bandavath said:
1 decade ago
p+q=5050*2=10100
q+r=6250*2=12500
p+r=5200*2=10400
than the total income is (p+q)+(q+r)+(p+r)= 133000
we have 2(p+q+r)=133000
next 2 dividing to 133000
It become p+q+r=16500
then we apply q+r values in there place
p+12500=16500
p=16500-12500
p=4000
Ok?
q+r=6250*2=12500
p+r=5200*2=10400
than the total income is (p+q)+(q+r)+(p+r)= 133000
we have 2(p+q+r)=133000
next 2 dividing to 133000
It become p+q+r=16500
then we apply q+r values in there place
p+12500=16500
p=16500-12500
p=4000
Ok?
Sana. said:
1 decade ago
Adding (i), (ii) and (iii), we get: 2(P + Q + R) = 33000 or P + Q + R = 16500 .... (iv)
Subtracting (ii) from (iv), we get P = 4000.
So why did we subtract from (ii) ?
Subtracting (ii) from (iv), we get P = 4000.
So why did we subtract from (ii) ?
Siva said:
1 decade ago
2p=2(5050+5200-6250)
=>p=4000
=>p=4000
Md hasim and km roy said:
1 decade ago
Simple method:.
p+q+r = 5050+5200 = 10250.
We have to subtract q+r from it. (ie) 6250.
10250-6250 = 4000 answer.
p+q+r = 5050+5200 = 10250.
We have to subtract q+r from it. (ie) 6250.
10250-6250 = 4000 answer.
SuniL said:
1 decade ago
It's not p=4000 it's p=2000
Let me explain
p+q=5050
q+r=6250
p+r=5200
Therefore we can write -
2(p+q+r)= 16500
p+q+r=16500/2
= 8250
p=8250-(q+r)
But we know that
q+r=6250
p=8250-6250
=2000
Hence p=2000
I hope everyone understand it.
Let me explain
p+q=5050
q+r=6250
p+r=5200
Therefore we can write -
2(p+q+r)= 16500
p+q+r=16500/2
= 8250
p=8250-(q+r)
But we know that
q+r=6250
p=8250-6250
=2000
Hence p=2000
I hope everyone understand it.
Upcoming aptitude warrior said:
1 decade ago
Friends p=4000 and not 2000.please read the question properly!!they have asked WHAT IS THE MONTHLY INCOME OF P AND NOT WHAT IS THE AVERAGE INCOME OF P.it is given "the average (THE KEY WORD IS AVERAGE!!) monthly income of P and Q is 5050" which means [(p+q)/2] = 5050.therefore the monthly income of p+q = 10100.
similarly the average income of q+r is 6250 which means [(q+r)/2]=6250.therefore the monthly income of q+r = 12500
and in the same manner,the average income of p+r is 5200 which means [(p+r)/2]=5200.therefore the monthly income of p+r is 10400.Now add p+q=10100 and p+r = 10400.therefore the answer is p+q+p+r=10100+10400=20500.So we get 2p+q+r=20500.now minus this with THE MONTHLY INCOME q+r=12500.The result is [(2p+q+r)-(q+r)]=[(20500)-(12500)]=8000.
so 2p=8000 (SINCE Q AND R GET CANCELLED)
P=4000
similarly the average income of q+r is 6250 which means [(q+r)/2]=6250.therefore the monthly income of q+r = 12500
and in the same manner,the average income of p+r is 5200 which means [(p+r)/2]=5200.therefore the monthly income of p+r is 10400.Now add p+q=10100 and p+r = 10400.therefore the answer is p+q+p+r=10100+10400=20500.So we get 2p+q+r=20500.now minus this with THE MONTHLY INCOME q+r=12500.The result is [(2p+q+r)-(q+r)]=[(20500)-(12500)]=8000.
so 2p=8000 (SINCE Q AND R GET CANCELLED)
P=4000
Clarification said:
1 decade ago
@Praveen's process simple n right..but he forget multiply r.h.s with 2 because it is average of two items.
Shiva said:
1 decade ago
P + Q = (5050 x 2) = 10100
Q + R = (6250 x 2) = 12500
P + R = (5200 x 2) = 10400
add above three
2(p+q+r)=33000
(p+q+r)=16500
we need 'p' only so
(p+q+r)-(q+r)=16500-12500
so p=4000...
Q + R = (6250 x 2) = 12500
P + R = (5200 x 2) = 10400
add above three
2(p+q+r)=33000
(p+q+r)=16500
we need 'p' only so
(p+q+r)-(q+r)=16500-12500
so p=4000...
Srinivas said:
1 decade ago
p+q= 5050
p+r=5200
total= 10250
here substract(-)q+r = 6250
p = 4000 (ans)
p+r=5200
total= 10250
here substract(-)q+r = 6250
p = 4000 (ans)
Rahul said:
1 decade ago
(p+q)/2 = 5050...(1)
(q+r)/2 = 6250...(2)
(p+r)/2 = 5200...(3)
From (1) and (2)
q=10100-p
r = 12500-q
Sub in (3)
p=10400-r
=10400-12500+q
=10400-12500+10100-p
p=(10400-12500+10100)/2=4000.
(q+r)/2 = 6250...(2)
(p+r)/2 = 5200...(3)
From (1) and (2)
q=10100-p
r = 12500-q
Sub in (3)
p=10400-r
=10400-12500+q
=10400-12500+10100-p
p=(10400-12500+10100)/2=4000.
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