Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 9)
9.
A car owner buys petrol at Rs.7.50, Rs. 8 and Rs. 8.50 per litre for three successive years. What approximately is the average cost per litre of petrol if he spends Rs. 4000 each year?
Answer: Option
Explanation:
| Total quantity of petrol consumed in 3 years |
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Total amount spent = Rs. (3 x 4000) = Rs. 12000.
 Average cost = Rs. |
 |
12000 x 51 |  |
= Rs. | 6120 | = Rs. 7.98 |
| 76700 | 767 |
Discussion:
93 comments Page 6 of 10.
Varma said:
1 decade ago
Why take 7.50 + 8 + 8.50 / 3 = 8?
Ashwini madne said:
1 decade ago
@Santhosh Sandy.
= 4000/7.50 + 4000/8 + 4000/8.50.
= 4000(1/7.50 + 1/8 + 1/8.50) ...... 1/7.50.
It can be written as 100/750 which is equal to 2/15 same as 1/8.50 can be written as 100/850 which is equal to 2/17.
= 4000(2/15 + 1/8 + 2/17).
= 4000[{(2 * 8) + (15 * 1)/15 * 8} + 2/17].
= 4000[{31/120 + 2/17}].
= 4000[767/2040].
= 76700/51.
= 4000/7.50 + 4000/8 + 4000/8.50.
= 4000(1/7.50 + 1/8 + 1/8.50) ...... 1/7.50.
It can be written as 100/750 which is equal to 2/15 same as 1/8.50 can be written as 100/850 which is equal to 2/17.
= 4000(2/15 + 1/8 + 2/17).
= 4000[{(2 * 8) + (15 * 1)/15 * 8} + 2/17].
= 4000[{31/120 + 2/17}].
= 4000[767/2040].
= 76700/51.
(1)
Santhosh Sandy said:
1 decade ago
In the solution how they got 4000(2/15+1/8+2/17) = (76700/51) ?
I'm bit confused :-(.
I'm bit confused :-(.
Henry said:
1 decade ago
When you say approximately. Is it wise to say the answer is 7.98 instead of 8.0 which is B?
Mounika said:
1 decade ago
Answer: 1503.92.
Subhasmita said:
1 decade ago
Please solve this equation 4000(2/15+1/8+2/17) = ?
Jeevan j said:
1 decade ago
At most one minute is the time available for this question. So further simplifications is required.
Gameruler said:
1 decade ago
How can we calculate this without using the calculator?
Abhishek said:
1 decade ago
Where 51 came from?
Gunwanti said:
1 decade ago
Can any one explain 76700/51?
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