Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 4)
4.
The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?
Answer: Option
Explanation:
Average of 20 numbers = 0.
Sum of 20 numbers (0 x 20) = 0.
It is quite possible that 19 of these numbers may be positive and if their sum is a then 20th number is (-a).
Discussion:
135 comments Page 9 of 14.
Sugi s said:
8 years ago
Thanks for your answer @Ravi.
Vignesh said:
8 years ago
For example : The Sum of first 19 number is 20 and the last number is -20. Therefore 20 -20 = 0.
Poonam said:
7 years ago
Thanks @Ravi.
Vignesh said:
7 years ago
1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1-19 = 0.
Therefore 0/20 =0.
Therefore 0/20 =0.
Sai said:
7 years ago
@All.
Why we think only one no is negative, let we think maybe 10 numbers -ve; i.e 10 numbers less than zero and 10 numbers is +ve i.e 10 numbers greater than zero. so the avg of -10 numbers and +10 numbers is equal to zero.
Why we think only one no is negative, let we think maybe 10 numbers -ve; i.e 10 numbers less than zero and 10 numbers is +ve i.e 10 numbers greater than zero. so the avg of -10 numbers and +10 numbers is equal to zero.
Subash said:
7 years ago
@Sai.
In the question, they had given AT THE MOST.
So, the maximum value must be the answer.
In the question, they had given AT THE MOST.
So, the maximum value must be the answer.
Saikat said:
7 years ago
Please anyone help I can't understand this.
Habib said:
7 years ago
Thanks @Praveen.
Denis said:
7 years ago
How? Explain me the answer.
Ankit Dere said:
7 years ago
It is asked in the question.
Avg of 20 numbers is Zero,
Given avg=0.
Numbers=20.
Explanation:
Avg=sum÷number i.e.
0=sum÷20
Now, cross multiply.
Sum=20x0=0.
This means the sum of 20 numbers is equal to 0.
{1+2+...+20}= is 0.
{1+2+...+19}= Will not be 0.
But the sum of rest 19 number will not be 0 it will be greater than 0(as the 2nd part of the question says how many may be greater than 0?)
Avg of 20 numbers is Zero,
Given avg=0.
Numbers=20.
Explanation:
Avg=sum÷number i.e.
0=sum÷20
Now, cross multiply.
Sum=20x0=0.
This means the sum of 20 numbers is equal to 0.
{1+2+...+20}= is 0.
{1+2+...+19}= Will not be 0.
But the sum of rest 19 number will not be 0 it will be greater than 0(as the 2nd part of the question says how many may be greater than 0?)
(5)
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