Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 3)
3.
A can contains a mixture of two liquids A and B is the ratio 7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained by the can initially?
Answer: Option
Explanation:
Suppose the can initially contains 7x and 5x of mixtures A and B respectively.
| Quantity of A in mixture left = | ![]() |
7x - | 7 | x 9 | ![]() |
litres = | ![]() |
7x - | 21 | litres. |
| 12 | 4 |
| Quantity of B in mixture left = | ![]() |
5x - | 5 | x 9 | ![]() |
litres = | ![]() |
5x - | 15 | litres. |
| 12 | 4 |
|
|
= | 7 | |||||
|
9 |
![]() |
28x - 21 | = | 7 |
| 20x + 21 | 9 |
252x - 189 = 140x + 147
112x = 336
x = 3.
So, the can contained 21 litres of A.
Discussion:
101 comments Page 9 of 11.
Kia said:
9 years ago
Let A initially be 7x & B be 5x.
The amount of A in a mixture is 7x /12& the amount of B in a mixture is 5x/12.
Let the total amount of mixture be x.
Now, it is given that 9litre of the mixture is taken out from the mixture & it can fill up with an amount of B.
Now, amount of new mixture be-
The Amount of A is 7(x-9)/12.
The amount of Bis 5(x-9)/12+9.
Now, it is given that the resultant ratio is 7/9.
7(X-9)/12:5(x-9)/12+9 = 7/9.
Now, it can easily solve to get the value of x=36 which is put in 7x/12 then get the amount of A is 21.
The amount of A in a mixture is 7x /12& the amount of B in a mixture is 5x/12.
Let the total amount of mixture be x.
Now, it is given that 9litre of the mixture is taken out from the mixture & it can fill up with an amount of B.
Now, amount of new mixture be-
The Amount of A is 7(x-9)/12.
The amount of Bis 5(x-9)/12+9.
Now, it is given that the resultant ratio is 7/9.
7(X-9)/12:5(x-9)/12+9 = 7/9.
Now, it can easily solve to get the value of x=36 which is put in 7x/12 then get the amount of A is 21.
Karen said:
9 years ago
Do we use the ratio? Please tell.
BDSHAHJAHAN said:
8 years ago
Good job @Silu, @Anilkumar.
Dhivya said:
8 years ago
Initial A:B 7:5 ->12Parts.
New ratio A:B 7:9.
In the new ratio only 4 parts is changed so, 4parts=9litre.
for 12 parts =27litre + 9Litre.
Initial Litre is 36.
for Initial liquid A :7/12 *36 = 21Litre.
New ratio A:B 7:9.
In the new ratio only 4 parts is changed so, 4parts=9litre.
for 12 parts =27litre + 9Litre.
Initial Litre is 36.
for Initial liquid A :7/12 *36 = 21Litre.
Dhivya said:
8 years ago
Initial A:B 7:5 ->12Parts.
New ratio A:B 7:9.
In the new ratio only 4 parts is changed so, 4parts=9litre.
for 12 parts =27litre + 9Litre.
Initial Litre is 36.
for Initial liquid A :7/12 *36 = 21Litre.
New ratio A:B 7:9.
In the new ratio only 4 parts is changed so, 4parts=9litre.
for 12 parts =27litre + 9Litre.
Initial Litre is 36.
for Initial liquid A :7/12 *36 = 21Litre.
Suri said:
8 years ago
The Whole Question is clear but Why we are Multiplying with 9 in ration (7/12) *9.
What does multiplying with 9 litres means?
Please answer thank you.
What does multiplying with 9 litres means?
Please answer thank you.
SAM said:
8 years ago
A : B.
7 : 5
7 : 9
Here A is not changed ,but B added 9 liters more,
B = 9 - 5 = 4 difference by adding 9 on [ 9+7=16].
9/4 * 16 = 36.
Total is 36.
A =36 * 7/12 = 21.
7 : 5
7 : 9
Here A is not changed ,but B added 9 liters more,
B = 9 - 5 = 4 difference by adding 9 on [ 9+7=16].
9/4 * 16 = 36.
Total is 36.
A =36 * 7/12 = 21.
Nihar said:
8 years ago
A:B=7:9.
So total=12 parts.
after removing 9 litres.
A:B=7:9,
so 4 parts of b = 9 litres(change in ratio of b).
1 part=9/4,
So for total of 12 parts = (9/4)*12=27.
remaining liquid = 27+9(from mixture).
=36.
So A quantity= (7/12)*36=21.
So total=12 parts.
after removing 9 litres.
A:B=7:9,
so 4 parts of b = 9 litres(change in ratio of b).
1 part=9/4,
So for total of 12 parts = (9/4)*12=27.
remaining liquid = 27+9(from mixture).
=36.
So A quantity= (7/12)*36=21.
Shashank Yadav said:
8 years ago
The simplest way to do this question:
A and B are in a ratio of 7:5, we can say that, A=7x. A should definitely be a multiple of 7 and hence 21 is the answer.
A and B are in a ratio of 7:5, we can say that, A=7x. A should definitely be a multiple of 7 and hence 21 is the answer.
Juli burnwal said:
8 years ago
Here we can see that there is only change in the liquid B.
7/5 (initially) and 7/9 (after drawn off the mixture and adding B).
So change in B liquid=9-5=4.
Now this 4 is the extra B liquid 5.
4 part=9lt.
So 12part (7+5) =27.
Now agn add the liquid mixture 9lt which was drawn off i.e 27+9=36lt.
Total=36lt.
So now A=36*7/12=21ans.
7/5 (initially) and 7/9 (after drawn off the mixture and adding B).
So change in B liquid=9-5=4.
Now this 4 is the extra B liquid 5.
4 part=9lt.
So 12part (7+5) =27.
Now agn add the liquid mixture 9lt which was drawn off i.e 27+9=36lt.
Total=36lt.
So now A=36*7/12=21ans.
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