Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 3)
3.
A can contains a mixture of two liquids A and B is the ratio 7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained by the can initially?
Answer: Option
Explanation:
Suppose the can initially contains 7x and 5x of mixtures A and B respectively.
Quantity of A in mixture left = | ![]() |
7x - | 7 | x 9 | ![]() |
litres = | ![]() |
7x - | 21 | ![]() |
12 | 4 |
Quantity of B in mixture left = | ![]() |
5x - | 5 | x 9 | ![]() |
litres = | ![]() |
5x - | 15 | ![]() |
12 | 4 |
![]() |
|
= | 7 | |||||
|
9 |
![]() |
28x - 21 | = | 7 |
20x + 21 | 9 |
252x - 189 = 140x + 147
112x = 336
x = 3.
So, the can contained 21 litres of A.
Discussion:
100 comments Page 8 of 10.
Gowtham said:
1 decade ago
Hi guys,
Find the pure liqued of A in initial
Assume pure liqued x,
Quantity of a measured left formula=(pure A liquid - mix liquid)
Pure liquid of A=7x
Mix liquid of A=(7/12)*9
here 9 is also mixture
So, quantity of a measured left A=(7x-(7/12)*9)=7x-21/4
the same rule
quantity of a measured left B=(5x-(5/12)*9)=5x-15/4
(7x-(21/4)/5x-(15/4)+9)=7/9
Given here that 9 is add with b
ans x=3
ratio of 7
So=7*3=21 that all
Find the pure liqued of A in initial
Assume pure liqued x,
Quantity of a measured left formula=(pure A liquid - mix liquid)
Pure liquid of A=7x
Mix liquid of A=(7/12)*9
here 9 is also mixture
So, quantity of a measured left A=(7x-(7/12)*9)=7x-21/4
the same rule
quantity of a measured left B=(5x-(5/12)*9)=5x-15/4
(7x-(21/4)/5x-(15/4)+9)=7/9
Given here that 9 is add with b
ans x=3
ratio of 7
So=7*3=21 that all
Prithvi chauhan said:
1 decade ago
Please can you explain in any other simple way?
Karthikeyini said:
1 decade ago
(7x-(21/4))/((5x-(15/4))+9)
In this term how 9 occured at the end ? Can anyone explain this ?
In this term how 9 occured at the end ? Can anyone explain this ?
Sree said:
1 decade ago
Hi Debjyoti,
Can you give the explination how you got x=36 using below equation?
7(x-9)/12:(5(x-9)+9) = 7:9
Can you give the explination how you got x=36 using below equation?
7(x-9)/12:(5(x-9)+9) = 7:9
Debjyoti said:
1 decade ago
Total mixer is x.
A=7x/12 B=5x/12
after drawn 9 lit of mixer........
mixer remain(x-9)
So the new ratio of A:B is ...
A=7(x-9)/12 and B=5(x-9)/12
now drawn 9 lit filled with B
so B now contain B=5(x-9)+9/12...........
now the new ratio of mixer is A:B=7:9
we know the new value of A and B...........put that in this equation
7(x-9)/12:(5(x-9)+9)=7:9-------if u calculate further u ll get the X value as 36
Put that x value in A=7x/12, so here you can get answer of A contain initially.
A=7x/12 B=5x/12
after drawn 9 lit of mixer........
mixer remain(x-9)
So the new ratio of A:B is ...
A=7(x-9)/12 and B=5(x-9)/12
now drawn 9 lit filled with B
so B now contain B=5(x-9)+9/12...........
now the new ratio of mixer is A:B=7:9
we know the new value of A and B...........put that in this equation
7(x-9)/12:(5(x-9)+9)=7:9-------if u calculate further u ll get the X value as 36
Put that x value in A=7x/12, so here you can get answer of A contain initially.
Amara said:
1 decade ago
How to calculate mixture left?
Ramakrishna said:
10 years ago
= (5x*4-15+9*4)/4.
Teja said:
1 decade ago
Can You explain in other way ?
Vini said:
9 years ago
If 1/4th of the total is 9.
That is, 1/4 * x = 9,
Then, total (x) = 36,
Therefore, 7/12 * 36 = 21.
That is, 1/4 * x = 9,
Then, total (x) = 36,
Therefore, 7/12 * 36 = 21.
Sonu said:
9 years ago
@ Prabhas,
Your explanation is very nice and it also very useful.
Your explanation is very nice and it also very useful.
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