Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 3)
3.
A can contains a mixture of two liquids A and B is the ratio 7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained by the can initially?
Answer: Option
Explanation:
Suppose the can initially contains 7x and 5x of mixtures A and B respectively.
Quantity of A in mixture left = | ![]() |
7x - | 7 | x 9 | ![]() |
litres = | ![]() |
7x - | 21 | ![]() |
12 | 4 |
Quantity of B in mixture left = | ![]() |
5x - | 5 | x 9 | ![]() |
litres = | ![]() |
5x - | 15 | ![]() |
12 | 4 |
![]() |
|
= | 7 | |||||
|
9 |
![]() |
28x - 21 | = | 7 |
20x + 21 | 9 |
252x - 189 = 140x + 147
112x = 336
x = 3.
So, the can contained 21 litres of A.
Discussion:
100 comments Page 5 of 10.
Juli burnwal said:
8 years ago
Here we can see that there is only change in the liquid B.
7/5 (initially) and 7/9 (after drawn off the mixture and adding B).
So change in B liquid=9-5=4.
Now this 4 is the extra B liquid 5.
4 part=9lt.
So 12part (7+5) =27.
Now agn add the liquid mixture 9lt which was drawn off i.e 27+9=36lt.
Total=36lt.
So now A=36*7/12=21ans.
7/5 (initially) and 7/9 (after drawn off the mixture and adding B).
So change in B liquid=9-5=4.
Now this 4 is the extra B liquid 5.
4 part=9lt.
So 12part (7+5) =27.
Now agn add the liquid mixture 9lt which was drawn off i.e 27+9=36lt.
Total=36lt.
So now A=36*7/12=21ans.
Arjun Mahatma said:
8 years ago
Thanks @Anil Kumar Jat.
Kashif said:
8 years ago
Totally wrong answers. Why because total qty of B solution after drawn off and portion of B added is this,
5/12*x - 9*5/12 + 4y < where why is total qty of B added after drawn off and 4=9-5>.
5/12*x - 9*5/12 + 4y < where why is total qty of B added after drawn off and 4=9-5>.
Prashant Pal said:
8 years ago
@ALL.
7:5
7:9
9-5= 4
7+5= 12
So,
4/12 * 9= 3
So 7*3= 21.
7:5
7:9
9-5= 4
7+5= 12
So,
4/12 * 9= 3
So 7*3= 21.
Sai sekhar said:
8 years ago
Given ratios A:B is 7:9 and asked the initial quantity for that we check the options which are the multiples of 7.
In this case, 21 is only multiple 7. So directly we can say 21 is the answer.
In this case, 21 is only multiple 7. So directly we can say 21 is the answer.
Confused.soul said:
7 years ago
A:B = 7:5
Total = 12 units
When 9 litres of mixture is removed, ((7/12) * 9) litres of A is removed, and ((5/12) * 9) litres of B is removed
Then 9 litres of B is added so that new ratio is 7:9.
In new mixture, Total volume of A is 7x - ((7/12) * 9) = 7x - 21/4.
And total volume of B is 5x - ((5/12) * 9) + 9 = 5x - 3 3/4 + 9 = 5x + 21/4,
So, (7x - 21/4)/(5x + 21/4) = 7/9.
Solving for x:
x=3.
Original Volume of A = 7x = 21,
Answer is D.
Total = 12 units
When 9 litres of mixture is removed, ((7/12) * 9) litres of A is removed, and ((5/12) * 9) litres of B is removed
Then 9 litres of B is added so that new ratio is 7:9.
In new mixture, Total volume of A is 7x - ((7/12) * 9) = 7x - 21/4.
And total volume of B is 5x - ((5/12) * 9) + 9 = 5x - 3 3/4 + 9 = 5x + 21/4,
So, (7x - 21/4)/(5x + 21/4) = 7/9.
Solving for x:
x=3.
Original Volume of A = 7x = 21,
Answer is D.
Confused.soul said:
7 years ago
The total mixer is x.
A=7x/12 B=5x/12
After drawn 9 lit of mixer.
As Now, the basic principle is that;
When you remove any amount of the mixture, it removes both the liquids in the same ratio as the mixture itself.
So by above ratio (7/12)*9 and (5/12)*9 are to be removed
7x/12-7*9/12 = 7(x-9)/12
5x/12-5*9/12 = 5(x-9)/12
A=7(x-9)/12 and B=5(x-9)/12
now drawn 9 lit filled with B.
so B now contains B=5(x-9)+9/12.
now the new ratio of mixer is A:B=7:9.
we know the new value of A and B...........put that in this equation
7(x-9)/12:(5(x-9)+9)=7:9 ------> if you calculate further you willl get the X value as 36.
Put that x value in A=7x/12, so here you can get answer of A contain initially.
A=7x/12 B=5x/12
After drawn 9 lit of mixer.
As Now, the basic principle is that;
When you remove any amount of the mixture, it removes both the liquids in the same ratio as the mixture itself.
So by above ratio (7/12)*9 and (5/12)*9 are to be removed
7x/12-7*9/12 = 7(x-9)/12
5x/12-5*9/12 = 5(x-9)/12
A=7(x-9)/12 and B=5(x-9)/12
now drawn 9 lit filled with B.
so B now contains B=5(x-9)+9/12.
now the new ratio of mixer is A:B=7:9.
we know the new value of A and B...........put that in this equation
7(x-9)/12:(5(x-9)+9)=7:9 ------> if you calculate further you willl get the X value as 36.
Put that x value in A=7x/12, so here you can get answer of A contain initially.
Lakshminarasimha said:
7 years ago
The total 9 drawn off ans filled.7:5,
3/4 parts drawnoff and filled,
For every 1part is 3 total 12 parts i.e 12*3=36,
7*3=21,5*3=15.
3/4 parts drawnoff and filled,
For every 1part is 3 total 12 parts i.e 12*3=36,
7*3=21,5*3=15.
Aksh said:
7 years ago
It is said that the ratio initially is 7:5, so the quantity of first is a multiple of 7, so 21 is the answer.
Ibu said:
7 years ago
Thanks @Debjyoti.
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