Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 4)
4.
A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?
Answer: Option
Explanation:
Let the cost of 1 litre milk be Re. 1
Milk in 1 litre mix. in 1st can = | 3 | litre, C.P. of 1 litre mix. in 1st can Re. | 3 |
4 | 4 |
Milk in 1 litre mix. in 2nd can = | 1 | litre, C.P. of 1 litre mix. in 2nd can Re. | 1 |
2 | 2 |
Milk in 1 litre of final mix. = | 5 | litre, Mean price = Re. | 5 |
8 | 8 |
By the rule of alligation, we have:
C.P. of 1 litre mixture in 1st can C.P. of 1 litre mixture in 2nd can | ||||||||
|
Mean Price
|
|
||||||
|
|
![]() |
1 | : | 1 | = 1 : 1. |
8 | 8 |
So, quantity of mixture taken from each can = | ![]() |
1 | x 12 | ![]() |
= 6 litres. |
2 |
Discussion:
74 comments Page 6 of 8.
Megh said:
10 years ago
Can any one tell me how did you get 5/8?
Anu said:
10 years ago
Please somebody clarify the logic behind that question in short way.
Dhruv Sahni said:
1 decade ago
Container A has 25% water, Container B has 50% of water and after mixing these two final mixture has 3/8 -> 37.5% of water.
So by allegation method the ratio of A and B in final mixture will be 25% 50% 37.5%.
50%-37.5% : 37.5%-25%.
= 12.5% = 12.5% = 1:1.
So Ratio of A:B in final mixture is 1:1, hence in 12 liter of mixture there will be 6L of A and 6L of B.
So by allegation method the ratio of A and B in final mixture will be 25% 50% 37.5%.
50%-37.5% : 37.5%-25%.
= 12.5% = 12.5% = 1:1.
So Ratio of A:B in final mixture is 1:1, hence in 12 liter of mixture there will be 6L of A and 6L of B.
Dhanwin said:
1 decade ago
Different approach:
==============
Can 1 ---- 25% water + 75% milk.
Ratio ---- 1:3 (25/75 = 1/3).
Can 2 ---- 50% water + 50% milk.
Ratio ----- 1:1 (50/50 = 1/1).
If I take p liters from can 1 and q liters from can 2.
So that total should be 12 liters with water : milk = 3 : 5.
So I get following equation.
P+q/3p+q = 3/5 -------- (equation 1).
Now try checking the given options in questions and the answer should be the "option" which satisfies the (equation 1).
Ex:
Let p = 6 and q = 6.
Then 6+6/(3*6+6) = 3/5.
So the equation 1 is satisfied. So the answer is 6 liters from can 1 and 6 liters from can 2.
Other options given won't satisfy the (equation 1).
==============
Can 1 ---- 25% water + 75% milk.
Ratio ---- 1:3 (25/75 = 1/3).
Can 2 ---- 50% water + 50% milk.
Ratio ----- 1:1 (50/50 = 1/1).
If I take p liters from can 1 and q liters from can 2.
So that total should be 12 liters with water : milk = 3 : 5.
So I get following equation.
P+q/3p+q = 3/5 -------- (equation 1).
Now try checking the given options in questions and the answer should be the "option" which satisfies the (equation 1).
Ex:
Let p = 6 and q = 6.
Then 6+6/(3*6+6) = 3/5.
So the equation 1 is satisfied. So the answer is 6 liters from can 1 and 6 liters from can 2.
Other options given won't satisfy the (equation 1).
Sri said:
1 decade ago
Can anybody tell me how 5/8 arrived here?
Sri Divya said:
1 decade ago
Hi friends, Please explain how 5/8 became the mean price?
How to calculate mean price?
How to calculate mean price?
Gokulpriya said:
1 decade ago
How did 5/8 become mean prize what is this value?
Ajay said:
1 decade ago
Cont 1 has 25% water and 75% milk.
Cont 2 has 50% water and 50% milk.
We take x lit mixture from cont 1.
25x/100 lit water and 75x/100 lit milk.
And take y lit mixture from cont 2.
50y/100 lit water and 50y/100 lit milk.
Ratio of water to milk = 25x+50y/75x+50y = 3/5.
From here x = y.
And total milk = 12 lit.
25x/100+75x/100+50y/100+50y/100 = 12 lit.
Put x = y.
Get answer as x = 6 and y = 6 lit.
And enjoy your day!
Cont 2 has 50% water and 50% milk.
We take x lit mixture from cont 1.
25x/100 lit water and 75x/100 lit milk.
And take y lit mixture from cont 2.
50y/100 lit water and 50y/100 lit milk.
Ratio of water to milk = 25x+50y/75x+50y = 3/5.
From here x = y.
And total milk = 12 lit.
25x/100+75x/100+50y/100+50y/100 = 12 lit.
Put x = y.
Get answer as x = 6 and y = 6 lit.
And enjoy your day!
(1)
Vaishnavi said:
1 decade ago
Please explain me in a simple way guys?
I can't get the logic?
I can't get the logic?
ANAND PATEL said:
1 decade ago
From the first can mixture is X liter.
From the first can mixture is Y liter.
NOW X + Y = 12.
IN 12 LITER portion of water is 4.5 and milk IS 7.5 LITER.
X( (1/4)+ (1/2))+ Y ((3/4)+(1/2))= 4.5 + 7.5.
SO X( (1/4)+ (1/2))= 4.5 => X= 6 LITER.
Y ((3/4)+(1/2)) = 7.5 +> Y = 6 LITER.
From the first can mixture is Y liter.
NOW X + Y = 12.
IN 12 LITER portion of water is 4.5 and milk IS 7.5 LITER.
X( (1/4)+ (1/2))+ Y ((3/4)+(1/2))= 4.5 + 7.5.
SO X( (1/4)+ (1/2))= 4.5 => X= 6 LITER.
Y ((3/4)+(1/2)) = 7.5 +> Y = 6 LITER.
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