Aptitude - Alligation or Mixture - Discussion

Discussion Forum : Alligation or Mixture - General Questions (Q.No. 4)
4.
A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?
4 litres, 8 litres
6 litres, 6 litres
5 litres, 7 litres
7 litres, 5 litres
Answer: Option
Explanation:

Let the cost of 1 litre milk be Re. 1

Milk in 1 litre mix. in 1st can = 3 litre, C.P. of 1 litre mix. in 1st can Re. 3
4 4

Milk in 1 litre mix. in 2nd can = 1 litre, C.P. of 1 litre mix. in 2nd can Re. 1
2 2

Milk in 1 litre of final mix. = 5 litre, Mean price = Re. 5
8 8

By the rule of alligation, we have:

C.P. of 1 litre mixture in 1st can    C.P. of 1 litre mixture in 2nd can
3
4
Mean Price
5
8
1
2
1
8
1
8

Ratio of two mixtures = 1 : 1 = 1 : 1.
8 8

So, quantity of mixture taken from each can = 1 x 12 = 6 litres.
2

Discussion:
74 comments Page 6 of 8.

Megh said:   10 years ago
Can any one tell me how did you get 5/8?

Anu said:   10 years ago
Please somebody clarify the logic behind that question in short way.

Dhruv Sahni said:   1 decade ago
Container A has 25% water, Container B has 50% of water and after mixing these two final mixture has 3/8 -> 37.5% of water.

So by allegation method the ratio of A and B in final mixture will be 25% 50% 37.5%.

50%-37.5% : 37.5%-25%.

= 12.5% = 12.5% = 1:1.

So Ratio of A:B in final mixture is 1:1, hence in 12 liter of mixture there will be 6L of A and 6L of B.

Dhanwin said:   1 decade ago
Different approach:
==============

Can 1 ---- 25% water + 75% milk.
Ratio ---- 1:3 (25/75 = 1/3).

Can 2 ---- 50% water + 50% milk.
Ratio ----- 1:1 (50/50 = 1/1).

If I take p liters from can 1 and q liters from can 2.

So that total should be 12 liters with water : milk = 3 : 5.

So I get following equation.

P+q/3p+q = 3/5 -------- (equation 1).

Now try checking the given options in questions and the answer should be the "option" which satisfies the (equation 1).

Ex:

Let p = 6 and q = 6.

Then 6+6/(3*6+6) = 3/5.

So the equation 1 is satisfied. So the answer is 6 liters from can 1 and 6 liters from can 2.

Other options given won't satisfy the (equation 1).

Sri said:   1 decade ago
Can anybody tell me how 5/8 arrived here?

Sri Divya said:   1 decade ago
Hi friends, Please explain how 5/8 became the mean price?

How to calculate mean price?

Gokulpriya said:   1 decade ago
How did 5/8 become mean prize what is this value?

Ajay said:   1 decade ago
Cont 1 has 25% water and 75% milk.
Cont 2 has 50% water and 50% milk.

We take x lit mixture from cont 1.
25x/100 lit water and 75x/100 lit milk.

And take y lit mixture from cont 2.
50y/100 lit water and 50y/100 lit milk.

Ratio of water to milk = 25x+50y/75x+50y = 3/5.

From here x = y.
And total milk = 12 lit.

25x/100+75x/100+50y/100+50y/100 = 12 lit.

Put x = y.

Get answer as x = 6 and y = 6 lit.

And enjoy your day!
(1)

Vaishnavi said:   1 decade ago
Please explain me in a simple way guys?

I can't get the logic?

ANAND PATEL said:   1 decade ago
From the first can mixture is X liter.

From the first can mixture is Y liter.

NOW X + Y = 12.

IN 12 LITER portion of water is 4.5 and milk IS 7.5 LITER.

X( (1/4)+ (1/2))+ Y ((3/4)+(1/2))= 4.5 + 7.5.

SO X( (1/4)+ (1/2))= 4.5 => X= 6 LITER.

Y ((3/4)+(1/2)) = 7.5 +> Y = 6 LITER.


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