Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 4)
4.
A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?
Answer: Option
Explanation:
Let the cost of 1 litre milk be Re. 1
| Milk in 1 litre mix. in 1st can = | 3 | litre, C.P. of 1 litre mix. in 1st can Re. | 3 |
| 4 | 4 |
| Milk in 1 litre mix. in 2nd can = | 1 | litre, C.P. of 1 litre mix. in 2nd can Re. | 1 |
| 2 | 2 |
| Milk in 1 litre of final mix. = | 5 | litre, Mean price = Re. | 5 |
| 8 | 8 |
By the rule of alligation, we have:
| C.P. of 1 litre mixture in 1st can C.P. of 1 litre mixture in 2nd can | ||||||||
|
Mean Price
|
|
||||||
|
|
|||||||
 Ratio of two mixtures = |
1 | : | 1 | = 1 : 1. |
| 8 | 8 |
| So, quantity of mixture taken from each can = |  |
1 | x 12 |  |
= 6 litres. |
| 2 |
Discussion:
74 comments Page 2 of 8.
XiYo said:
4 years ago
Nice Explaination @Hardick!
Shivam said:
4 years ago
@Hardik.
Nice explanation!
Nice explanation!
Hardik said:
4 years ago
The initial ratio of water to milk in can 1 is 1:3.
Initial ratio of water to milk in can 2 is 1:1.
If we add both then we get the ratio of water to milk 2:4.
It is said that this ratio becomes 3:5.
So from 2:4, it becomes 3:5.
As we can see there is an equal amount of change 3-2 = 1 and 5-4 = 1.
Therefore the quantity also should be in the ratio of 1:1.
Hence the answer is 6:6.
Initial ratio of water to milk in can 2 is 1:1.
If we add both then we get the ratio of water to milk 2:4.
It is said that this ratio becomes 3:5.
So from 2:4, it becomes 3:5.
As we can see there is an equal amount of change 3-2 = 1 and 5-4 = 1.
Therefore the quantity also should be in the ratio of 1:1.
Hence the answer is 6:6.
(71)
B.M. Nasim Reza Anik said:
4 years ago
If 1 litre is drawn from the 1st container, we get 0. 25L water and 0. 75L milk and if 1 litre is drawn from the 2nd container, we get 0.5L water and 0.5L milk.
By combining 1L from each of the two containers, we get 0. 75L water and 1.25L milk. In which water to milk is in the ratio of 3:5.
Thus we need 2+2+2+2+2+2 to get 12L in total and 6L from each of the containers.
By combining 1L from each of the two containers, we get 0. 75L water and 1.25L milk. In which water to milk is in the ratio of 3:5.
Thus we need 2+2+2+2+2+2 to get 12L in total and 6L from each of the containers.
(3)
Sasi said:
5 years ago
x -> quantity from A.
y -> quantity grom B.
x + y = 12;
0.25x + 0.5y = (3/8)*12.
Solving for x and y we get an answer.
y -> quantity grom B.
x + y = 12;
0.25x + 0.5y = (3/8)*12.
Solving for x and y we get an answer.
(1)
Muslih said:
5 years ago
As per allegation, we obtained that same quantity are taken from each Can.
So (.75)*x+(.5)*x=12 milk in the new mix, where x-> quantity mixer taken from can1 and can2(1:1).
X=12*4/5.
MILK FROM CAN 1 is = (.75) * 12 * 4/5 = 36/5 = 7.2..
Milk from can 2 is =.(.5) * 12 * 4/5 = 24/5 = 4.8.
Hence answer for the quantity of milk collected from each CAN to get the 12lit of milk is 7.2 and 4.8 respectively.
Am I right?
So (.75)*x+(.5)*x=12 milk in the new mix, where x-> quantity mixer taken from can1 and can2(1:1).
X=12*4/5.
MILK FROM CAN 1 is = (.75) * 12 * 4/5 = 36/5 = 7.2..
Milk from can 2 is =.(.5) * 12 * 4/5 = 24/5 = 4.8.
Hence answer for the quantity of milk collected from each CAN to get the 12lit of milk is 7.2 and 4.8 respectively.
Am I right?
Harshada said:
5 years ago
Well explained @Kunal.
Surya said:
5 years ago
Can anyone tell how we are multiplying 1/2 with 12?
Andy said:
5 years ago
Three parts milk and 1 part water in one container and 1 part milk and 1 part water in the second container.
Representing the milk 3x/4+1x/2 = 7.5(5/8*12) Solving x you get 6.
Representing the water 1x/4+1x/2 = 4.5(3/8*12) Solving x you get 6.
Representing the milk 3x/4+1x/2 = 7.5(5/8*12) Solving x you get 6.
Representing the water 1x/4+1x/2 = 4.5(3/8*12) Solving x you get 6.
Sabbir said:
5 years ago
You can solve the math in this way as well,
In can1 there is 25% (1/4) water and 75% (3/4) milk.
Again, in can2 there is 50% (1/2) water and 50% (1/2) milk.
So, total volume of water = 1/4+1/2 = 3/4.
Total volume of milk = 3/4+1/2 = 5/4.
Now, as per the question, the ratio of water and milk must be 3x and 5x.
So, we can write, 3/4:5/4 = 3x:5x.
Or, 3/4* 5x = 5/4 * 3x.
Or, 15x/4 = 15x/4.
That's to say the volume of water and milk must be the same. Hence the answer will be 6 liters.
In can1 there is 25% (1/4) water and 75% (3/4) milk.
Again, in can2 there is 50% (1/2) water and 50% (1/2) milk.
So, total volume of water = 1/4+1/2 = 3/4.
Total volume of milk = 3/4+1/2 = 5/4.
Now, as per the question, the ratio of water and milk must be 3x and 5x.
So, we can write, 3/4:5/4 = 3x:5x.
Or, 3/4* 5x = 5/4 * 3x.
Or, 15x/4 = 15x/4.
That's to say the volume of water and milk must be the same. Hence the answer will be 6 liters.
(3)
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