Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 6)
6.
A dishonest milkman professes to sell his milk at cost price but he mixes it with water and thereby gains 25%. The percentage of water in the mixture is:
Answer: Option
Explanation:
Let C.P. of 1 litre milk be Re. 1
Then, S.P. of 1 litre of mixture = Re. 1, Gain = 25%.
C.P. of 1 litre mixture = Re. | ![]() |
100 | x 1 | ![]() |
= | 4 |
125 | 5 |
By the rule of alligation, we have:
C.P. of 1 litre of milk C.P. of 1 litre of water | |||||
Re. 1 | Mean Price
| 0 | |||
|
|
![]() |
4 | : | 1 | = 4 : 1. |
5 | 5 |
Hence, percentage of water in the mixture = | ![]() |
1 | x 100 | ![]() |
= 20%. |
5 |
Discussion:
65 comments Page 3 of 7.
Satadhi said:
7 years ago
Is 25% gain means he must have added 25% of water. So if 100lts of milk is there then you have 25lts of water. So part of solution which is water is 25/125. Then convert this into percentage.
(1)
Tushar said:
7 years ago
The solution is;
Water/milk * 100 is the formula for solving this.
Initially, water is 25% so remaining milk is 75% which makes W:M=1:4.
%water = w/total*100 and %milk= m/total*100 so %water = 1/5*100 = 20%.
Water/milk * 100 is the formula for solving this.
Initially, water is 25% so remaining milk is 75% which makes W:M=1:4.
%water = w/total*100 and %milk= m/total*100 so %water = 1/5*100 = 20%.
Cesoul said:
7 years ago
let 100 litres of milk costs ---> x rs.
Now, they say how much water needs to be added to milk, we shall get 25 % gain
so,
100 lit milk+ y litres water costs --> x + 25 * X/100.
re-arranging the above equations
100 lit --> x rs.
100 lit + y litres water ---> x + 0.25x (adding the gain).
Cross multiply.
(x+0.25x) * 100 = 100*x + y*x.
solving we get;
25x = x * y.
y = 25 litres of water.
So now total mixture ( 100 lit milk + 25 lit of water ) = 125 lit of mixture.
to find out the percentage of water in 125 litres.
25*100/125 = 20 litre of water.
Now, they say how much water needs to be added to milk, we shall get 25 % gain
so,
100 lit milk+ y litres water costs --> x + 25 * X/100.
re-arranging the above equations
100 lit --> x rs.
100 lit + y litres water ---> x + 0.25x (adding the gain).
Cross multiply.
(x+0.25x) * 100 = 100*x + y*x.
solving we get;
25x = x * y.
y = 25 litres of water.
So now total mixture ( 100 lit milk + 25 lit of water ) = 125 lit of mixture.
to find out the percentage of water in 125 litres.
25*100/125 = 20 litre of water.
LALIT KAUSHAL said:
7 years ago
Formula is; (R/R+100)*100 So, ( 25/25+100)*100=20%.
Thuder said:
7 years ago
Suppose 1 litre is 1rs.
Then 0.5 litres is 0.5 right.
x litres cost x rupee,
So gain = ((s.p-c.p)/c.p)*100;
So he actually sells it for 1 rupee as 1 litre of milk but he has less than 1 litre of milk, say x,
So x litres cost x rupee,
So 25=((1-x)/x)*100;,
x=4/5;,
So water is 1/5 which is 20%,
Hope it helps.
Then 0.5 litres is 0.5 right.
x litres cost x rupee,
So gain = ((s.p-c.p)/c.p)*100;
So he actually sells it for 1 rupee as 1 litre of milk but he has less than 1 litre of milk, say x,
So x litres cost x rupee,
So 25=((1-x)/x)*100;,
x=4/5;,
So water is 1/5 which is 20%,
Hope it helps.
Shree said:
7 years ago
Thank you all for explaining it.
Siva said:
8 years ago
Simple.
Gain=25.
Total milk =125.
Then 25/125=20%.
Gain=25.
Total milk =125.
Then 25/125=20%.
Bhagyasri said:
8 years ago
Suppose Milk man have 100 litre he want sell same 100 litre by adding some water.
Milk...................100 litre(initially)
Milk+ water.......100 litre(after addition of milk)
So, milk = 100-water.
Now, cost price Rs/-100.
Because of 25% profit selling price Rs/-125
100 * 100 = (100-water) * 125.
Water = 20.
Out of 100 litre water quantity is 20 litre.
So, answer is 20%.
Milk...................100 litre(initially)
Milk+ water.......100 litre(after addition of milk)
So, milk = 100-water.
Now, cost price Rs/-100.
Because of 25% profit selling price Rs/-125
100 * 100 = (100-water) * 125.
Water = 20.
Out of 100 litre water quantity is 20 litre.
So, answer is 20%.
(2)
Reisang Kasar said:
8 years ago
Please someone help me.
How to find out the weight of the water mixed in gm per kilogram of milk?
How to find out the weight of the water mixed in gm per kilogram of milk?
Naux said:
8 years ago
Say the vendor buys L liters of milk and the cost of this is X.
Now, the vendor mixes some amount of water so the quantity is becoming say (L+Z) the cost of this is X(original cost)+25/100(X) that would be 5X/4.
Cost---->quantity
X---->L
5X/4--->?
So, ? = 5L/4,
So (L+Z) = 5L/4,
Z =L/4,
So, that would be 25% right but the answer is 20%.
Now, the vendor mixes some amount of water so the quantity is becoming say (L+Z) the cost of this is X(original cost)+25/100(X) that would be 5X/4.
Cost---->quantity
X---->L
5X/4--->?
So, ? = 5L/4,
So (L+Z) = 5L/4,
Z =L/4,
So, that would be 25% right but the answer is 20%.
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