Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 6)
6.
A dishonest milkman professes to sell his milk at cost price but he mixes it with water and thereby gains 25%. The percentage of water in the mixture is:
Answer: Option
Explanation:
Let C.P. of 1 litre milk be Re. 1
Then, S.P. of 1 litre of mixture = Re. 1, Gain = 25%.
C.P. of 1 litre mixture = Re. | ![]() |
100 | x 1 | ![]() |
= | 4 |
125 | 5 |
By the rule of alligation, we have:
C.P. of 1 litre of milk C.P. of 1 litre of water | |||||
Re. 1 | Mean Price
| 0 | |||
|
|
![]() |
4 | : | 1 | = 4 : 1. |
5 | 5 |
Hence, percentage of water in the mixture = | ![]() |
1 | x 100 | ![]() |
= 20%. |
5 |
Discussion:
65 comments Page 2 of 7.
Mashiur said:
5 years ago
Let, CP=SP = x
CP of Milk(M) = Mx
SP of Milk & Water(M+W) = (M+W)x,
Now, (M+W)x-Mx = Mx/4,
M:W = 4:1.
CP of Milk(M) = Mx
SP of Milk & Water(M+W) = (M+W)x,
Now, (M+W)x-Mx = Mx/4,
M:W = 4:1.
(4)
Karthi said:
6 years ago
Excellent @Amir.
Arun said:
6 years ago
Here gain%/100 + gain%*100 it means 25/100 + 25*100 = 20%.
Vihan said:
6 years ago
If the price of milk is 15% more than that of water than the price of water is how much percent less than that of milk? Can anyone solve this?
Nisha said:
6 years ago
25 %= 1/4,
So 4 is milk and 1 is water,
4+1 =5 is milk and water.
1/5 * 100 = 20%.
So 4 is milk and 1 is water,
4+1 =5 is milk and water.
1/5 * 100 = 20%.
(3)
Palash said:
6 years ago
Let 1 lt milk price is rs1 and x lt water mixed.
Then CP of (1-x)lt milk is rs(1-x) and SP is rs 1.
So, x/ (1-x) = 25% implies X= 20%.
Then CP of (1-x)lt milk is rs(1-x) and SP is rs 1.
So, x/ (1-x) = 25% implies X= 20%.
Karan said:
7 years ago
If we apply alligation on % profit i.e. if he sell the milk at CP, he gains 0% and if he sell water at CP, he gains 100%. Thus by rule of alligation the ratio comes out to be 3:1.
& in that case % water in mixture becomes 25%. Now, by solving it by the method given and the method used by me, I m getting confused what is the perfect answer. Can anyone help?
& in that case % water in mixture becomes 25%. Now, by solving it by the method given and the method used by me, I m getting confused what is the perfect answer. Can anyone help?
Ramesh said:
7 years ago
CP of milk = X.
SP of Milk = X.
He did not get any profit so he mixed some water and sold it. Then he got a profit of 25%
SP of mixture=1.25X.
1.25X = X + 0.25X.
x = milk and 0.25X = water.
we need to calculate how much water is there in the mixture.
0.25X/1.25X = 0.2.
---->20% water.
SP of Milk = X.
He did not get any profit so he mixed some water and sold it. Then he got a profit of 25%
SP of mixture=1.25X.
1.25X = X + 0.25X.
x = milk and 0.25X = water.
we need to calculate how much water is there in the mixture.
0.25X/1.25X = 0.2.
---->20% water.
Bathi said:
7 years ago
x liters of milk ------- re.1.
(x+y) liters of mixture -------- re.1.25 where y is for water.
(x+y)/x = 1.25/1.
y/x = 1/4.
y = 1/5 * 100 = 20%.
(x+y) liters of mixture -------- re.1.25 where y is for water.
(x+y)/x = 1.25/1.
y/x = 1/4.
y = 1/5 * 100 = 20%.
Priya said:
7 years ago
I am unable to understand. Please, anybody explain me clearly.
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