Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 7)
7.
How many kilogram of sugar costing Rs. 9 per kg must be mixed with 27 kg of sugar costing Rs. 7 per kg so that there may be a gain of 10% by selling the mixture at Rs. 9.24 per kg?
Answer: Option
Explanation:
S.P. of 1 kg of mixture = Rs. 9.24, Gain 10%.
![]() |
![]() |
100 | x 9.24 | ![]() |
= Rs. 8.40 |
110 |
By the rule of allilation, we have:
C.P. of 1 kg sugar of 1st kind Cost of 1 kg sugar of 2nd kind | ||
Rs. 9 | Mean Price Rs. 8.40 | Rs. 7 |
1.40 | 0.60 |
Ratio of quantities of 1st and 2nd kind = 14 : 6 = 7 : 3.
Let x kg of sugar of 1st be mixed with 27 kg of 2nd kind.
Then, 7 : 3 = x : 27
![]() |
![]() |
7 x 27 | ![]() |
= 63 kg. |
3 |
Discussion:
40 comments Page 4 of 4.
P.s.manikanta said:
1 decade ago
Observe the allegation method which is given as solution. They are mixed in the ratio 1.40:0.60 =14:60. This ratio always remains constant in allegation. They have already given 27kg for sugar costing 7rs/- per kg. The question asked is how many (?) kgs of sugar costing 9rs/- per kg should be mixed. So equate the ratio of weights.
Vijay said:
1 decade ago
Solve in another method: Amount of 1st kind 'x'and its cost Rs.9/kg and amount of 2nd kind is 27kg and its cost is 7/kg.
c.p of mixture=(9x+(27*7))
s.p of mixture=9.24*(27+x)
Profit=(s.p-c.p)/c.p=10/100
Then we get x value.
c.p of mixture=(9x+(27*7))
s.p of mixture=9.24*(27+x)
Profit=(s.p-c.p)/c.p=10/100
Then we get x value.
Ram said:
1 decade ago
How the 14:6 come can any one explain ?
May said:
1 decade ago
Can explain me for ratio ??
Sri said:
1 decade ago
Mean price?
Raji said:
1 decade ago
Sorry I cant understood what amit said. Kindly explain it.
Amit said:
1 decade ago
its simple
(quantity of cheaper/quantity of dearer=cp of dearer-mean price)/(cp of cheaper/cp of mean).
So 27/x=0.6/1.4
x=63.....
So simple
(quantity of cheaper/quantity of dearer=cp of dearer-mean price)/(cp of cheaper/cp of mean).
So 27/x=0.6/1.4
x=63.....
So simple
Rahul said:
1 decade ago
This is same as last problem. Here goes:
Selling price is 9.24 and profit is 10% so:
Cost price + Profit = Selling Price
Let cost price be equal to x:
x + 0.1x = 9.24
1.1x = 9.24
x = 924/11 which is 8.4
Then you do alligation which is shown in the explanation to bring the ratio of Rs. 9 sugar to Rs. 7 sugar down to 7:3
So Amount of Rs. 9 sugar (lets call it A) is related to amount of Rs. 7 sugar by the following formula:
A/27 = 7/3 (since we found out the ratio they are in)
Now solve for A by cross multiplying:
3A = 27 x 7
A = (27 x 7)/3 [27/3 reduces down to 9) = 9 x 7 = 63kg
Selling price is 9.24 and profit is 10% so:
Cost price + Profit = Selling Price
Let cost price be equal to x:
x + 0.1x = 9.24
1.1x = 9.24
x = 924/11 which is 8.4
Then you do alligation which is shown in the explanation to bring the ratio of Rs. 9 sugar to Rs. 7 sugar down to 7:3
So Amount of Rs. 9 sugar (lets call it A) is related to amount of Rs. 7 sugar by the following formula:
A/27 = 7/3 (since we found out the ratio they are in)
Now solve for A by cross multiplying:
3A = 27 x 7
A = (27 x 7)/3 [27/3 reduces down to 9) = 9 x 7 = 63kg
Suhani said:
1 decade ago
Hi,
How the C. P is calculated?
How the C. P is calculated?
Sivaram said:
1 decade ago
Hi Friends,
I can't understand why we take x to b mixed with 27kg of sugar (last step).
Please some one help me out. Thank you.
I can't understand why we take x to b mixed with 27kg of sugar (last step).
Please some one help me out. Thank you.
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