Aptitude - Alligation or Mixture - Discussion
Discussion Forum : Alligation or Mixture - General Questions (Q.No. 11)
11.
Find the ratio in which rice at Rs. 7.20 a kg be mixed with rice at Rs. 5.70 a kg to produce a mixture worth Rs. 6.30 a kg.
Answer: Option
Explanation:
By the rule of alligation:
Cost of 1 kg of 1st kind Cost of 1 kg of 2nd kind | ||
720 p | Mean Price 630 p | 570 p |
60 | 90 |
Required ratio = 60 : 90 = 2 : 3.
Discussion:
30 comments Page 3 of 3.
Vaishnavi said:
1 decade ago
No its 2:3 only.
How it comes is that,
-> (6.30-7.20)=> -0.60.
-> (5.70-6.30)=> -0.90.
Upon equating them acc to allegations rule, you get,
0.2:0.3 which will be 2:3;
I guess it comes this way..am I right?
How it comes is that,
-> (6.30-7.20)=> -0.60.
-> (5.70-6.30)=> -0.90.
Upon equating them acc to allegations rule, you get,
0.2:0.3 which will be 2:3;
I guess it comes this way..am I right?
Oldman said:
1 decade ago
Let the ratio be x/1-x
Then
7.20 (1-x) + 5.70 x = 6.30
7.20 -7.20x + 5.70x =6.30
7.20-1.50x =6.30
7.20-6.30 /1.50 =x
0.90/1.50 = x
3/5 =x
1-x = 1-3/5 =2/5
x/1-x = 3/5 /2/5 = 3/2
Then
7.20 (1-x) + 5.70 x = 6.30
7.20 -7.20x + 5.70x =6.30
7.20-1.50x =6.30
7.20-6.30 /1.50 =x
0.90/1.50 = x
3/5 =x
1-x = 1-3/5 =2/5
x/1-x = 3/5 /2/5 = 3/2
Sakshi said:
1 decade ago
According to books cheaper price shoul b taken firtt then dearer. So I think answer is 3:2. Please clear my doubt m I right?
Vasumaila said:
1 decade ago
worth of cost=6.30
so 6.30*100=630
den
720-630=90
630-570=60
so
90:30=2:3
so 6.30*100=630
den
720-630=90
630-570=60
so
90:30=2:3
(1)
Hari said:
1 decade ago
How 630 came?
VARUN KUMAR said:
1 decade ago
Rule of Alligation : If two ingredients are mixed, then :
c = Cost price of a unit quantity of cheaper
d= C.P. of a unit quantity of dearer
(Quantity of Cheaper) / (Quantity of dearer) = {(C.P. of Dearer) - (Mean price)} / {(Mean Price) - (C.P. of Cheaper)}
(Cheaper quantity) : (Dearer quantity) = (d - m) : (m - c)
c d
\ /
\/
/\mean price (m)
/ \
(d-m) (m-c)
c = Cost price of a unit quantity of cheaper
d= C.P. of a unit quantity of dearer
(Quantity of Cheaper) / (Quantity of dearer) = {(C.P. of Dearer) - (Mean price)} / {(Mean Price) - (C.P. of Cheaper)}
(Cheaper quantity) : (Dearer quantity) = (d - m) : (m - c)
c d
\ /
\/
/\mean price (m)
/ \
(d-m) (m-c)
(1)
Nitin gusain said:
1 decade ago
Yes @Angeeta according me you are right.
I think it is a mistake.
It should be 90:60 or 3:2.
I think it is a mistake.
It should be 90:60 or 3:2.
(1)
Angeeta said:
1 decade ago
According to the formula the cheaper price is came frist and bearer price is second. so according to me the answer is 90:60=3:2
am i right?
am i right?
Chirag said:
1 decade ago
@Ajay
630 - 570 = 60 and
720 - 630 = 90
It is simple.
630 - 570 = 60 and
720 - 630 = 90
It is simple.
Ajay said:
1 decade ago
How 60 & 90 came here?
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