Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 31)
31.
The bending stress in a beam is __________ section modulus.
Discussion:
12 comments Page 1 of 2.
Asma said:
4 years ago
Nice explanation @Dev.
Naresh jetti said:
8 years ago
Bending stress=pe/Z.
Where
P=load.
e=max bending moment.
Z=section modulus.
Where
P=load.
e=max bending moment.
Z=section modulus.
Dev said:
8 years ago
As bending stress = My/I.
= M/(I/y),
= M/z.
Where z = section modulus.
= M/(I/y),
= M/z.
Where z = section modulus.
(1)
Sambit said:
9 years ago
What is section modulus?
Saurabh said:
9 years ago
Section modulus Z = I/Y -----------equation (1).
Bending Equation = M/I = F/Y = E/R.
M/I = F/Y.
M/F = I/Y.
Than from equation (1).
Z = M/F.
Which show the section modulus is inversely proportional to Bending stress.
Bending Equation = M/I = F/Y = E/R.
M/I = F/Y.
M/F = I/Y.
Than from equation (1).
Z = M/F.
Which show the section modulus is inversely proportional to Bending stress.
(1)
Pankaj said:
10 years ago
Section modulus is Z = I/Y.
Bending moment is M = Stress*Z.
So stress = 1/Z*m.
Bending moment is M = Stress*Z.
So stress = 1/Z*m.
Shivu said:
1 decade ago
Section modulus is the ratio between moment of inertia to the distance from neutral axis to extreme fiber.
Babubhilare said:
1 decade ago
Bending moment = Moment of resistance.
M/I = sigma/Y.
M = sigma/Y *I.
But I /Y = Section modulus i.e. = Z.
M = sigma*Z.
OR.
M/Z = sigma.
Due to which bending stress (sigma) is inversely proportional to section modulus.
M/I = sigma/Y.
M = sigma/Y *I.
But I /Y = Section modulus i.e. = Z.
M = sigma*Z.
OR.
M/Z = sigma.
Due to which bending stress (sigma) is inversely proportional to section modulus.
Vanraj said:
1 decade ago
What means modulus?
Hariprasad said:
1 decade ago
Section modulus is the ratio of bending moment to bending stress. So the bending stress is indirectly propositional to section modulus.
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