General Knowledge - Chemistry - Discussion
Discussion Forum : Chemistry - Section 1 (Q.No. 32)
32.
The mass of one Avogadro number of helium atom is
Discussion:
16 comments Page 1 of 2.
Poonam bhelave said:
2 years ago
I think the right Answer D.
Versha said:
4 years ago
In question, Helium atom is given which means its elemental state (He) not its molecular state (He2). So, the correct answer of mass of helium atom is 2 gm not 4 gm.
Versha said:
4 years ago
In question, Helium atom is given which means its elemental state (He) not its molecular state (He2). So, the correct answer of mass of helium atom is 2 gm not 4 gm.
Skp said:
6 years ago
That the Avogadrods no is divided by the mass no * Avogadro's number. Then answer is 4.00gm.
Anom said:
6 years ago
It's said "1 Avogadro's number"! so 4.00 will be the answer.
Tera baap said:
6 years ago
Thanks all for explaining.
Psycho said:
7 years ago
Can anyone help me to understand the answer?
Arun said:
7 years ago
@Vijay.
You explained good.
You explained good.
Rojalin said:
8 years ago
I too have the same doubt @Mira.
Please anyone clear our doubts.
Please anyone clear our doubts.
(1)
Yusuf said:
9 years ago
One mole of helium is equal to one mole of avogardoes constant which is equal to 4 grams of helium.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers