Engineering Mechanics - General Principles - Discussion
Discussion Forum : General Principles - General Questions (Q.No. 3)
3.
Determine the angle
: = 30° = 40° = 60° = 50°Discussion:
30 comments Page 1 of 3.
Manali Chowdhury said:
8 years ago
In the triangle one is 90° angle, and the same another angle of 40° in the same direction is also a 40° angle because it is placed on the same line.
So, the other angle is θ.
So, as we know the hole angle of a triangle is 180°.
Therefore, solution,
40° + θ +90° = 180°.
Or, θ + 90° = 180° - 40°.
Or, θ + 90° = 140°.
Or, θ= 140° - 90°.
Or, θ = 50°.
So, the angle θ is 50°.
Thanking you.
So, the other angle is θ.
So, as we know the hole angle of a triangle is 180°.
Therefore, solution,
40° + θ +90° = 180°.
Or, θ + 90° = 180° - 40°.
Or, θ + 90° = 140°.
Or, θ= 140° - 90°.
Or, θ = 50°.
So, the angle θ is 50°.
Thanking you.
Nkayawa muhidini said:
10 years ago
Okay I understanding that question but I need more explain.
N.Sakthi said:
10 years ago
I cannot understand.
Edy said:
1 decade ago
Total Angle 1 Triangle = 180.
Know One Angle 40.
So 40 + 90 + X = 180.
X = 180 - 90 + 40.
X = 180 - 130.
X = 50.
Know One Angle 40.
So 40 + 90 + X = 180.
X = 180 - 90 + 40.
X = 180 - 130.
X = 50.
Lakshmi said:
1 decade ago
In 1st figure:
The two lines are parallel hence it is 40.
Since it is a straight line it makes 180.
Hence 180-40 = 140.
Theta = 140-90 = 50.
Same in the second and third figure.
The two lines are parallel hence it is 40.
Since it is a straight line it makes 180.
Hence 180-40 = 140.
Theta = 140-90 = 50.
Same in the second and third figure.
Himanth venati said:
1 decade ago
From fig 2:
90+40+x = 180.
130+x = 180.
x = 50.
90+40+x = 180.
130+x = 180.
x = 50.
Er. jagdeep yadav said:
1 decade ago
In 2nd fig.
One angle is 90degree.
One angle is alternate which is 40 degree.
So total is 180 on a line then.
90+40+x=180.
X=180-130.
X=50.
One angle is 90degree.
One angle is alternate which is 40 degree.
So total is 180 on a line then.
90+40+x=180.
X=180-130.
X=50.
Karthik said:
1 decade ago
IN fig1 consider triangle ABC the angle A was 40 B was 90 then C WAS 50 now we draw perpendicular line to B 90 - 50=40 incliantion line angle 40 so 90 -40=50=theata.
Desingu said:
1 decade ago
In third figure, if you just remove the 40 degree line (only imagination)you can see right angle triangle, so that 90-40=50 degree. As per the rules is 50 degree
Manish yadav said:
1 decade ago
In first figure, angle b/w two line is 90 then
40+90+x=180.
X=50.
40+90+x=180.
X=50.
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