"I never see what has been done; I only see what remains to be done."
- Marie Curie
26.
A and B can do a work in 8 days, B and C can do the same work in 12 days. A, B and C together can finish it in 6 days. A and C together will do it in :
so c's 1 day's work=1/6-1/8=1/24
and a's 1 day's work=1/6-1/12=1/12
and b's 1 day work=1/6(1/24+1/12)=1/4
so a and c 1'day work=1/12+1/24=1/8
Akiii said:
(Sun, Mar 27, 2011 12:02:53 PM)
Good explanation.
Azuu said:
(Thu, Aug 11, 2011 10:20:57 AM)
How to take lcm of 1/8+1/12 ?
Sabarimani said:
(Mon, Aug 15, 2011 06:17:54 PM)
Is b's 1day work=1/6-(1/24+1/12)?
Gulshan said:
(Sat, Oct 22, 2011 02:58:23 PM)
24 is lcm of 8 & 12
Kavitha said:
(Mon, Feb 20, 2012 12:52:19 PM)
Why did you take 1/6 (1/12+1/24) ?
Anishkumar said:
(Wed, Mar 7, 2012 09:48:55 PM)
Assume A+C as x
so now
2(A+B+C)=1/8+1/12+1/x
2(1/6) =5/24+1/x
finally
x =8
Parveen Verma said:
(Tue, Mar 20, 2012 08:30:24 PM)
(A+B+C)=1/6
A's one day work work= (A+B+C)-(B+C)= 1/6-1/12 =1/12
C's one day work work= (A+B+C)-(A+B)= 1/6-1/8= 1/24
(A+C)'s one day work= 1/12+1/24= 1/8
so the work will be completed in 8 days
Sujeet said:
(Fri, Apr 20, 2012 12:52:41 AM)
Why 2 is multiplied by 1/6.
Basu said:
(Wed, Sep 5, 2012 12:01:48 PM)
How its come on 1/6-1/2=1/12
1/6-1/8= 1/24
1/12+1/24= 1/8
Why 2 is multiplied with 1/6 ? please explain any one.
Nik said:
(Sat, Sep 22, 2012 07:37:19 PM)
1 day's work of(A+B)=1/8
1 day's work of (B+C)=1/12
lets take 1 day's work of (A+C)=1/x
adding the above we get 2(A+B+C)=1/8+1/12+1/X
dr4 2(1/6)=(1/8)+(1/12)+(1/x)
1/x=(2/6)-(1/8)-(1/12)
1/x=1/8
Dhanshree said:
(Tue, Mar 19, 2013 04:04:28 PM)
(A+B) work is = 1/8.
(B+C)work is = 1/12.
(A+B+C)work is = 1/6.
Only A's work = 1/6-1/12
= 1/12.
Only C's work=1/6-1/8
= 1/24.
Hence (A+C)'s complete work is = (1/12+1/24)
= 1/8.
(A+C)'s complete work in 8 day.
Monu said:
(Sat, Apr 27, 2013 01:34:02 PM)
Why can't we simply subtract A+B's 1 day work from B+C's 1 day work to get A+C's 1 day work?
Sk.Gopinath said:
(Mon, May 20, 2013 06:39:08 PM)
A+B+C = 1/6;
A+B = 1/8;
B+C = 1/12;
C's 1day work is =>1/6 - 1/8
=>1/24.
A's 1day work is =>1/6 - 1/12
=>1/8.
(A + C)'s 1 day's work
