Aptitude - Time and Work
Exercise : Time and Work - General Questions
- Time and Work - Formulas
- Time and Work - General Questions
- Time and Work - Data Sufficiency 1
- Time and Work - Data Sufficiency 2
- Time and Work - Data Sufficiency 3
26.
A and B can do a work in 8 days, B and C can do the same work in 12 days. A, B and C together can finish it in 6 days. A and C together will do it in :
Answer: Option
Explanation:
| (A + B + C)'s 1 day's work = | 1 | ; |
| 6 |
| (A + B)'s 1 day's work = | 1 | ; |
| 8 |
| (B + C)'s 1 day's work = | 1 | . |
| 12 |
(A + C)'s 1 day's work |
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So, A and C together will do the work in 8 days.
27.
A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in:
Answer: Option
Explanation:
| (B + C)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 7 | . |
| 9 | 12 | 36 |
| Work done by B and C in 3 days = | ![]() |
7 | x 3 | ![]() |
= | 7 | . |
| 36 | 12 |
| Remaining work = | ![]() |
1 - | 7 | ![]() |
= | 5 | . |
| 12 | 12 |
| Now, | 1 | work is done by A in 1 day. |
| 24 |
| So, | 5 | work is done by A in | ![]() |
24 x | 5 | ![]() |
= 10 days. |
| 12 | 12 |
28.
X can do a piece of work in 40 days. He works at it for 8 days and then Y finished it in 16 days. How long will they together take to complete the work?
Answer: Option
Explanation:
| Work done by X in 8 days = | ![]() |
1 | x 8 | ![]() |
= | 1 | . |
| 40 | 5 |
| Remaining work = | ![]() |
1 - | 1 | ![]() |
= | 4 | . |
| 5 | 5 |
| Now, | 4 | work is done by Y in 16 days. |
| 5 |
| Whole work will be done by Y in | ![]() |
16 x | 5 | ![]() |
= 20 days. |
| 4 |
X's 1 day's work = |
1 | , Y's 1 day's work = | 1 | . |
| 40 | 20 |
| (X + Y)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 3 | . |
| 40 | 20 | 40 |
| Hence, X and Y will together complete the work in | ![]() |
40 | ![]() |
= 13 | 1 | days. |
| 3 | 3 |
29.
A and B can do a job together in 7 days. A is 1
times as efficient as B. The same job can be done by A alone in :
times as efficient as B. The same job can be done by A alone in :Answer: Option
Explanation:
| (A's 1 day's work) : (B's 1 day's work) = | 7 | : 1 = 7 : 4. |
| 4 |
Let A's and B's 1 day's work be 7x and 4x respectively.
| Then, 7x + 4x = | 1 | 11x = |
1 | x = |
1 | . |
| 7 | 7 | 77 |
A's 1 day's work = |
![]() |
1 | x 7 | ![]() |
= | 1 | . |
| 77 | 11 |
30.
A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?
Answer: Option
Explanation:
Let A's 1 day's work = x and B's 1 day's work = y.
| Then, x + y = | 1 | and 16x + 44y = 1. |
| 30 |
| Solving these two equations, we get: x = | 1 | and y = | 1 |
| 60 | 60 |
B's 1 day's work = |
1 | . |
| 60 |
Hence, B alone shall finish the whole work in 60 days.
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(A + C)'s 1 day's work

11x =