Why should not subsract with 854? Please clear my doubt....

Priya said:
(Mon, Nov 29, 2010 10:04:37 AM)

@Lavanya and kanna

To get 1 year difference we have to subtract
4year amount-3year amount
this difference amount is the 1 year simple interest..
that's why..
Rs. (854 - 815) = Rs. 39
39 is 1year S.I.

hope it helps you..

Nag said:
(Tue, Feb 8, 2011 10:15:04 AM)

Thank you. This is explanation is very helpful for me.

Appu said:
(Mon, Feb 21, 2011 08:29:22 PM)

Hai friends,

Principle is the amount borrowed. Here, explain about SI of 3 years and 4 years. Assume P is the principal then, P+854 for 4 years and p+815 for 3yrs.

So here it is necessary to find the SI of one year and subtract it from the 3 year or 4 year.

That is, (815-117) = 698 and 854-156=698.

Vishnu said:
(Tue, Mar 8, 2011 05:03:11 AM)

To get a si of one year or it might be two years if it is two year we have to divide it by two si=3yrs -2yrs willl give u one year si why should we have to go to risk.

Ramesh said:
(Fri, Mar 18, 2011 07:15:04 AM)

PTR/100 = 815
P*3*R/100 = 815
R/100=854- 815
p * 3 * 39 = 815
P * 117 = 815
p = 815-117 = 698

Hari said:
(Sat, Mar 26, 2011 03:14:01 AM)

I like this type of solutions thank you

I think this answer also

1year 854-815=39

3years 39*4=156

854-156=698

Vijay said:
(Fri, May 27, 2011 12:52:26 AM)

What is formula of simpe interest ?

Rajini Kumar said:
(Fri, Jun 3, 2011 12:38:38 PM)

S.Ib = PNR/100

Narasimha Reddy said:
(Sat, Jun 4, 2011 07:01:21 AM)

S.I=PTR/100

Gayathri said:
(Wed, Jun 22, 2011 01:15:27 AM)

Hi Friends!
Principle = the amt u borrowed
Interest = the small additional amt u pay for the amt u
borrowed

First let me explain u d question
In the question,
A sum of money at simple interest amounts to Rs. 815 in 3 years means the Principle amt together wit the interest paid for 3 yrs is Rs. 815 and similarly Principle amt together wit the interest paid for 4 yrs is Rs. 854

Therefore, if we subtract (854-815) we get the simple interest for 1 year as Rs. 39

Then, we calculate simple interest for 3 yrs as (39*3)= 117

Next step, we subtract (815 - 117) to get Principle amt for a yr as Rs. 698

Brief explanation for last step:

815 = Principle amt + int for 3 yrs ......equation 1
117 = int for 3 yrs ......equation 2

now subtract both equations, we get the principle amt

(815 - P)/(854 - P) = 3/4
Solving this eq, we get
P = 698

Uma said:
(Tue, Aug 16, 2011 09:40:22 PM)

@gayathri your explination is very helpfull.

Thank you.

Harsh said:
(Tue, Sep 13, 2011 08:29:52 PM)

I am not deciding which is easiest way to solve of the given question so please suggest me.

Venkatesh said:
(Mon, Sep 19, 2011 12:35:32 PM)

Gayathri thank you so much before that I want to say myself I am dull even though I understood you are explantion it is very clear keep it up.

Jaya said:
(Mon, Sep 26, 2011 08:45:43 PM)

Gayathri thanks a lot its vry clr & simple

Kichu said:
(Mon, Oct 24, 2011 07:03:35 PM)

Thanks gayathri.

Muskan said:
(Sun, Nov 20, 2011 03:53:53 PM)

Please give me the solution of this question.

A certain sum given on simple interest became double in 20 years. In how many years will it be 4 times.

Ranjitha said:
(Tue, Dec 27, 2011 10:54:07 PM)

Its same friends.. you can do it in either way
(39*4)=156
854-159=698 only

Sonia said:
(Thu, Dec 29, 2011 08:12:49 PM)

Thanks Gayathri. Really your explanation is helpful.

Venkatesh Kumar said:
(Tue, Jan 17, 2012 09:12:48 PM)

Thanks Gayathti for giving detailed explanation.

Saurabh said:
(Tue, May 1, 2012 12:30:27 AM)

Thanks gayathri.

Tejashree said:
(Fri, Jun 8, 2012 09:21:58 PM)

Thanks gayathri

Radhika said:
(Sat, Jun 23, 2012 01:18:17 PM)

Thank you so much Gayathri.... very good explaination

Moksh said:
(Sat, Jul 21, 2012 12:06:23 AM)

@Gayathri.

Thanks a lot dear.

Very useful answer :).

Ismail Khan said:
(Fri, Aug 17, 2012 12:33:54 AM)

Amount for three years is 815
so AMOUNT= p + SI
A = p + pin
815= p + 3pi.......... (1)
similerly for 4 years
854 = p +4pi..........(2)
subtracting equation (1) from(2) we get
39 = pi
or
pi =39
put this value of pi in equation (1) we get
815= p+ 3*39
815= p+ 117
815-117=p
p=698

Satish said:
(Mon, Sep 3, 2012 09:43:34 AM)

@Gayahthri explained good .

Sudesna said:
(Wed, Sep 4, 2013 03:01:15 PM)

When we apply the formula SI = PRT/100.

And when we apply the formula Amount = P+SI.

Sumit Singh said:
(Mon, Dec 23, 2013 09:16:13 AM)

815 ------ 854 (This value 39 increase in 1 year ).

So in four year 39*4/156.

This 156 is interest in four year.

So principle is equal to / 854-156 equal to 698.

Varunraj said:
(Sat, Jan 4, 2014 03:51:30 PM)

If we take for four years.

39*4 = 156.

854-156 = 698 is the answer.

If we take three years.

39*3 = 117.

815-117 = 698 the answer is same !

We can do both the way.

Ravi said:
(Fri, Mar 28, 2014 05:00:20 PM)

If in this question asked rate also then how to solve this question?

Nishan said:
(Thu, Jul 10, 2014 10:56:35 PM)

In my view the interest between the 3rd & 4th year of Rs. 39/- cannot determine the same interest component for the first three years as the interest will be paid on top of the capital?

As such the interest component should reduce proportionately over the previous years?

Narendra said:
(Wed, Aug 13, 2014 02:32:09 PM)

SI1 = 815.
SI2 = 854.

DIFFERENCE = SI2-SI1.
D = 854-815.
D = 39.

FOR 3 YEARS = 3*39.
= 117.

SO NOW P = 815-117.
P = 698.

Rafee And Guru said:
(Tue, Aug 19, 2014 10:24:17 AM)

Hi Friends!

Principal = the amount you borrowed.
Interest = the small additional amount you pay for the amount you borrowed.

First let me explain you the question.
In the question,

A sum of money at simple interest amounts to Rs. 815 in 3 years means the Principal amount together with the interest paid for 3 yrs is Rs. 815 and similarly Principal amount together with the interest paid for 4 yrs is Rs. 854

Therefore, if we subtract (854-815) we get the simple interest for 1 year as Rs. 39.

Then, we calculate simple interest for 3 yrs as (39*3) = 117.

Next step, we subtract (815 - 117) to get Principal amt for a yr as Rs. 698.

Brief explanation for last step:

815 = Principal amt + int for 3 yrs ......equation 1.
117 = int for 3 yrs ......equation 2.

Now subtract both equations, we get the principal amount

I hope that this explanation will be helpful to you.

Priyanka said:
(Sun, Nov 16, 2014 04:35:04 PM)

Hi friends.

Here goes the explanation,

SI for 4 years = Rs 854.
SI for 3 years = Rs 815.

{4-3} = 1.

So SI for 1 year can be {854-815}.
= Rs 39.

So the SI for 3 years can be {39*3}.
= 117.

So principal is 815-117.
= RS 698{ANS}.

Magesh said:
(Sun, Nov 23, 2014 05:03:20 PM)

For four years the interest is,

854-815 = 39.
39*4 = 156.

So 854-156 = 698.

It may simple one no need to apply any formulas here. Time waste one.

Stuti said:
(Sat, Mar 21, 2015 08:54:24 PM)

Hi.

There is a simple shortcut for solving this question.

P/Sum = A1n2-A2n1/n2-n1.

= 815*4-854*3/4-3.

= 3260-2562/1 = 698.

Shaminzu said:
(Mon, Jul 20, 2015 07:50:25 PM)

3y---815.
4y---854.
------------
1y---39.

3y---39*3 = 117 or 4y---39*4 = 156.

815-117 = 698 or 854-156 = 698.

So we could subtract by 854 or 815.

All The best. Think smart.

Monika said:
(Fri, Oct 16, 2015 03:42:34 PM)

Can explain me logic behind it?

Prasad said:
(Thu, Oct 29, 2015 02:58:08 PM)

Will you elaborate it in understanding way?

Md Sahil said:
(Sat, Jan 9, 2016 08:59:35 AM)

Sum amounts to 815 in 3 years.

Sum amounts to 854 in 4 years.

Find sum?

Let the sum be Rs. x.

x = principal amounts in 3 years = Rs. 815.

x = principal amounts in 4 years = Rs. 854.

Principal amount in 1 year = 39 I.

Interest of 1 year = Rs. 39.

Interest of 3 year = 3x39= Rs. 117.

Principal = x.
Rate = ?
Time = 3 years.
For 3 years.

Interest = Rs. 117.
Amount = Rs. 815.
Time = 3 years.