Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 24)
24.
Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?
10
12
15
20
Answer: Option
Explanation:

Speed of the first train = ( 120 ( m/sec = 12 m/sec.
10

Speed of the second train = ( 120 ( m/sec = 8 m/sec.
15

Relative speed = (12 + 8) = 20 m/sec.

Therefore Required time = [ (120 + 120) ] sec = 12 sec.
20

Discussion:
22 comments Page 1 of 3.

AUNRAJ JAGTAP said:   7 months ago
Very nice, Thanks for explaining the answer.

Nikhil said:   5 years ago
Speed of T1 = 120/10 = 12m/s.
Speed of T2 = 120/15 = 8m/s.

Time taken to cross each other = D/S = (120 + 120)/12 + 8 = 12 secs.
(3)

Shweta said:   6 years ago
Why didn't we take (15+10) directly as speed like we add in other questions.
(1)

Srijan das said:   6 years ago
The answer should be 6.

And 120m should be the length considered for the opposite direction.

When travelling in same direction, the length should be 120+120.
(1)

Sam said:   6 years ago
This problem should tell us,two trains are coming from opposite sid.
(1)

Shree said:   7 years ago
Thank you all for explaining the answer.

Priya said:   8 years ago
Why are we not calculate this way,

s = 120+120/10+15,
= 9.6 m/s.

Correct me if I am wrong.
(1)

Akhilesh said:   9 years ago
Anyone can explain this problem? because I'm not understand this problem.

Vinayak PB said:   9 years ago
It's simple, just add both train durations i.e. 10s + 15s = 25s.

And just check mid point ie 25/2.

We get 12.5 so literally equal to 12s.

Harishankar said:   9 years ago
We will add 120 + 120 because of two different speeds of trains. If both trains having equal length and equal speed its not necessary to add lengths.
(2)


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