Here, 20% of a=b i.e.,(20/100)a=b
then, b%20 i.e.,(b/100)*20---I
then sub b=(20/100)a in I
we get,
=(20/100)a * (1/100) * 20
=(20/100)a * (20/100)
=(400/10000)a
=(4/100)a
= 4% of a
Habiba said:
(Wed, Dec 7, 2011 02:24:57 PM)
A man bought a pen for #15 and later sold the pen for #60. What was the percent increase in the price of the pen?
Cosmicguypradeep said:
(Sun, Dec 11, 2011 08:52:17 PM)
@habiha
here is the answer
% increase = (actual increase/original price *100)%
% decrease = (actual decrease/ original price *100)%
so, for this question we have to calculate % increase (since the pen was sold at higher rate 45, which was actually bought for 15 Rs)
(60-15/15 *100)% = 300%.
Mahesh said:
(Sun, Jan 15, 2012 01:32:01 AM)
In earlier sum, how
=(20/100)a * (1/100) * 20 comes,
because if we sub b=(20/100)a in I then that equ'n comes like
((20/100)a)/100*20 then how it comes (20/100)a * (1/100) * 20
Kcs said:
(Wed, Mar 21, 2012 04:51:36 PM)
Take a=100
b=20%a=20%100=20/100*100=20
b=20
20%b=20/100*20=4
4%a=4%100=4
5%a=5%100=5
20%a=20%100=20
ans=4%.
b% of 20 =
