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Aptitude - Clock - Discussion

@ : Home > Aptitude > Clock > General Questions - Discussion

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"Two things are infinite: the universe and human stupidity; and I'm not sure about the universe."
- Albert Einstein
3. 

A clock is started at noon. By 10 minutes past 5, the hour hand has turned through:

[A]. 145º[B]. 150º
[C]. 155º[D]. 160º

Answer: Option A

Explanation:

Angle traced by hour hand in 12 hrs = 360º.

Angle traced by hour hand in 5 hrs 10 min. i.e., 31 hrs = 360 x 31 º = 155º.
6 12 6


Uma said: (Thu, Jul 1, 2010 01:02:33 AM)    
 
I can't understand how that 31/6 come?

Pradeep Gorai said: (Fri, Jul 2, 2010 01:24:45 PM)    
 
To Uma
5 hr 1o min=310min(5*60+10)
=310/60 hr
=31/6 hr.
or
5 hr 10 min=5+10/60
=31/6

Nilesh said: (Sat, Jul 3, 2010 05:12:27 AM)    
 
I cant undrstand how that
31/6 hrs= (360/12 * 31/6) = 155

Pradeep said: (Sun, Jul 4, 2010 01:22:44 AM)    
 
to nilesh
1hr=30 degree
.'. 31/6 hr= 31/6 * 30 =155 deg

Sandhya said: (Wed, Jul 28, 2010 08:34:12 AM)    
 
5.10/60
=5.2/12
=5.1/6
=5*6+1/6
=31/6

Mariah said: (Thu, Oct 21, 2010 06:37:10 AM)    
 
What is the formula of changing minutes or hours to degrees?

Nitin Harjai said: (Mon, Mar 21, 2011 01:04:53 PM)    
 
I don't understand "by 10min past 5".

Akshay said: (Sun, Apr 3, 2011 05:50:52 AM)    
 
10min past 5 is 5:10
so, 5+10/60 =5+1/6(cross multiply)=31/6

Naveed Mohammad said: (Wed, Jun 29, 2011 11:21:16 AM)    
 
Formula for finding degree when min and hr ar given is

angle = (11/2)*m - 30*h when (11/2)*m > 30*hr
angle = 30*hr-(11/2)*m when (30hr > (11/2)*m

where m = min, hr = hours

=30*5-(11/2)*10
=150-(120/2)
=(300-120)/2
=180/2
=90 degrees

Its a time institute materiel solution.

Resham said: (Wed, Aug 10, 2011 11:39:47 AM)    
 
Initially both hands are at 12(noon)
1 hr= 30 dgrs ( 12 to 5 = 5 hrs)
so 5*30 = 150 dgrs and
in 60 mins cover 30 dgrs
in 10 mins= 30/60
in 1 min= 30/60*10= 5 dgrs
so
150 + 5 = 155 dgrs

Narendran, S S said: (Sat, Aug 13, 2011 04:21:06 PM)    
 
Angle between hr and min is given by

A =30*hr~(11/2)*min
= 30*5 - (11/2)*10
= 95 degrees

Now the angle swiped by the min hand alone is

6 degrees per min
hence 60 degrees per 10 min

Angle swiped by hr hand alone is
A+60 = 95+60 = 155 degrees.

Navaneetha Krishnan said: (Sun, Aug 28, 2011 09:41:36 PM)    
 
Sir i can't understand that 155 degree for which timing?

Vinay said: (Mon, Aug 29, 2011 12:14:32 PM)    
 
It is for 5 hours 10 minutes from noon (12).

Shravan Purohit said: (Thu, Sep 8, 2011 10:02:18 AM)    
 
@navaneetha

Given : our hour hand started at noon i.e. 12 o'clock
and 10 minutes past 5 i.e. 5 hour 10 minutes
we find angle between 12 and 5.10 o'clock
firstly we convert 5hour 10min into minitus 5*60+10=310min
and 310min convert into hour 310/60=31/6

In 12h = 360
So in 31/6 h= (360/12)(31/6)=155 degree.

Kranti said: (Wed, Dec 7, 2011 02:58:21 PM)    
 
Very nice explanatoin given by shravan.

Madesh said: (Wed, Jan 4, 2012 11:34:47 PM)    
 
Don't worry I will explain Clearly....

Past 5 means 5 hours.. and 10 mins out of 60 mins.. that's (10/60)

So.. 5hrs + 10 mins= 5+(10/60) = 5+(1/6).. so. 6*5+1= 31/6hrs..

1hr= 30 degree... so 5hrs= 150 degree and that past 5(means 5degree)...

So 150+5 = 155.

Leenus said: (Mon, Jan 23, 2012 12:21:05 PM)    
 
I can't understand "by 10 mins past 5".

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