INFOSYS PAPER - 09 OCT 2005 - BANGALORE
I was shortlised in the written test and I attended the interview .Hopefully waiting for the result. And one more thing, they r checking the rough work so don't by heart and write.
1.There are 100 students among them 10 dont study both physics and chemistry,63 studying physics,85 studying chemistry. how many of them are studying both chemistry and physics (3 mark)
2. sal and saul are taking part in 100 yards running race in which sal beats saul by 10 yards. If sal starts 10 yards behind the starting line who will win the race?
Ans;sal wins saul by 1 yard, because as sal covers 10 yards saul covers only 9 yards.
3.This problem is like .....
IF A= 4,A+B+C+D = D+E+G+H=G+H+I=17..
whats the value of D and G. (6 mark)
ans; d=5 g=1
4.In a dice the nos 1&6, 2&5, 3&4 are to be in opposite face . how many chances are there to attain this by satisfying the above condition.... (3 mark)
Ans: 48(u need to place the nos in the die in such a way it satisfies all the condition i.e. right-1 left-6 top-2 bottom-5 front-3 back-4
5.In this problem , they gave 6 equations ..
upto 6 equations.. (8 mark)
and ask us to find out the value of each variable. in this type of problem just cancel the common variables in given equation by either addition or subtraction.
6.there are two cans A&B can A contains water, can B contains pure milk .first double the amount of liquid in can B by adding water from can A , the double the content of can A by adding content of can B, then finally double the amount of can B by can A at last the amount in both the cans are equal and the water in can B is 1 gallon more the amount of milk .find the amount of milk &water start with. (6 mark)
7.Jan robinson, kate jones, john smith are engineer, pilot & biochemist not in the order .they have three martian assistants . as they find difficulty with martian names they gave them nick names as smith, robinson, jones as their masters name.
1.robinson is an yomi
2.all martians speak uri.
3.the martians name is the same as the bio chemist is naim
4.robinson beats engineer in the chess
(one more condition) who is the pilot?
dont remember exactly..
Ans :Jan robinson
8. This problem was to arrange 7 gems in right & left window 3 in each very easy ..this question carries 8 marks...
Its easy.... U can do it..
9.a parent has 15 children who where born in an interval of 1.5 years each . the first child`s age is 8 times that of last child. what's the age of the first child? (4M)
Ans: X=8Y, X=Y+21 Solving X=24
10.Sita goes to Gita's house during vacation. they play a game of chess everyday and the loser has to give a chocolate to the winner for every game . Sita gave 8 chocolates to Gita at the end of the vacation, although she had won 12 games. How long did she stay there? 5 marks
Ans : 32 days(doubt)I put as 31
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