Placement Papers - HCL

PAPER: HCL Placement Paper and Pattern (Technical)

Section I: computer awareness
 
Section II: Simple C- language
 
Section III: On pointers & structures and C++, JAVA(only 1 on this)
 
Section IV: Analytical
 
  1. Which of the following involves context switch,
 
(a) system call (b) privileged instruction) floating point exception) all the above (e) none of the above
 
Ans: (a)
 
2. In OST, terminal emulation is done in
 
(a) sessions layer b) application layer c) presentation layer (d) transport layer
 
Ans: (b)
 
3. For a 25MHz processor , what is the time taken by the instruction which needs 3 clock cycles,
 
(a)120 nano secs(b)120 micro secs(c)75 nano secs(d)75 micro secs ans a
 
4. For 1 MB memory, the number of address lines required,
 
(a)11 (b)16 (c)20(d) 24
 
Ans. (c)
 
5. Semaphore is used for
 
(a) synchronization b) dead-lock avoidance (c) box (d) none
 
Ans. (a)
 
6. Parity error checking is used for.........?
 
Ans: a odd numbers of errors
 
7. Address on internet are (Internet IP address is unique for..)
 
a) unique for particular domain
 
b) unique for a particular sub-node list
 
c) unique countrywide
 
d) unique in a network area
 
Ans: b has to be unique in the sub network
 
8. one ans is c Volatile modifier
 
9. OLE is used in
a) inter connection in Unix
 
b) interconnection in WINDOWS
 
c) interconnection in WINDOWS NT
 
ans c(check)
 
10. Convert a given HEX number to OCTAL
 
  11. Macros and function are related in what aspect?
 
(a) recursion
 
(b) varying no of arguments
 
(c) hypo checking
 
(d) type declaration
 
Ans d or a (check)
 
12.Preprocessor does not do which one of the following
 
(a) macro
 
(b) conditional complication
 
(c) in type checking
 
(d) including load file
 
Ans. (c)
 
13. Piggy backing is a technique for
 
a) Flow control
 
b) Sequence
 
c) Acknowledgement
 
d) retransmission
 
Ans. (c)
 
14. In signed magnitude notation what is the minimum
 
value that can be represented with 8 bits
 
(a) -128
 
(b) -255
 
(c) -127
 
(d) 0
 
Ans a
 
15. There is an employer table with key fields as employer number data in every n\'th row are needed for a simple following queries will get required results.
 
(a) select A employee number from employee A , w here exists from employee B where A employee no. = B employee having (count(*) mod n)=0
 
(b) select employee number from employe A, employe B where A employe number=B employ number group by employee number having(count(*) mod n=0 )
 
(c) both (a) & (b)
 
(d) none of the above
 
15. Type duplicates of a row in a table customer with on uniform key field customer number you can see
 
a) delete from customer where customer number exists (select distinct customer number from customer having count )
 
b) delete customer a where customer number in b rowid

c) delete customer a where customer number in( select customer number from customer a, customer b )
 
d) none of the above