Placement Papers - Cisco

Cisco Systems
CISCO PAPER - 17 OCT 2004 - BANGALORE
Posted by :
Samn
(21)
Cisco test Conducted on 17th sunday october at bangalore there were almost 40 technical questions and 10 analytical questions..total 50 questions..

Analytical questions

1. find perimeter of a trapezium wit 3 sides given and distance b/w parallel sides given...

2. A triangle ABC is given, a line DE is paralel to base side and that cuts the triangle.. the ratio of area of triangle to the area of trapezium .given DE/BC= 3/5..

3. four concentric circles r given .the radius of 1st circle is x.next is 2x,then 3x and 4x. given that area b/w 2nd and 1st is A and 4th and 3rd circles being B. find ratio of A to B

4. Difference b/w the perimeteres of two concentric circles is 66. find the difference b/w radius..
ans 10.5

5. 3/p=6,3/q=15......find p-q

Technical questions.....
6. #define clrscr() 100
main()
{
clrscr();
printf("%d",clrscr());


7. which of the followin is used for avoidin network congestion
bufferin
cachin
sourcequench
all of de above

8. main()
{
int a;
printf("%d",scanf(%d,&a));
}
wats o/p of this pgm..wat will b printed
ans :0

9. main()
{
printf("as");
printf("hi");
printf("is
");
} wat will b printed.

10.main()
{
unsigned short a=-1;
unsigned char b=a;
printf("%d %d ",a,b);
}
wat is o/p of the program
a. 65535 -1
b. 65535 65535
c. -1 -1

11. arrays base address is 1000....array is a[5][4]..then wat is de correct address of a[4][3]...
ans:1056

12. one packet is 64bytes..no of pkts send is 16000..then total no of bytes send is
ans 1024000

13. #define maxval 5
int main (void)
{
int i=1;
if(i-maxval)
{
printf("inside");
}
else
{
printf("out");
}
find o/p???

14. #define a 3+3
#define b 11-3
main()
{
printf("%d",a*b);
}
wat is o/p?????

15. A question in which segment address is given ..logical address is 800. base addresses also given ..u hav 2 find physical address..

16. There was a question on processor speed in nanocycles..then it performs a instruction in x cycles..dont remember

17. main()
{
int *i;
int s=(int *)malloc(10*sizeof(int));
for (i=0;i<10;i++)
{
printf("%d",i*i)
}
wats o/p