Online Electronics and Communication Engineering Test - Electronics and Communication Engineering Test - Random
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- Total number of questions: 20.
- Time allotted: 30 minutes.
- Each question carries 1 mark; there are no negative marks.
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- All the best!
Marks : 2/20
Test Review : View answers and explanation for this test.
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v1 = 100 sin (ωt + 15°) and v2 = 60 cos ωt = 60 sin (ωt + 90°). Hence, v2 is leading v1 by (90 - 15) = 75°.
A = 14.14Ð45°, loge A = loge 14.14 x
= 2.65 + j 0.785.
Assertion (A): Thevenin's theorem and Norton's theorem are dual of each other.
Reason (R): Voltage source can be converted into current source and vice versa.
Thevenin's circuit uses a voltage source and Norton's circuit uses a current source.
ICBO = (400 x 10-9) 2(80-25)/10 = 18 μA.
Because of high input impedance and low output impedance, CC amplifier is suitable as buffer amplifier.
1101 = 13 in decimal = 15 (i.e., 8 + 5) in octal.
In synchronous counter time delay is constant while in Ripple it is additive.
- that it is depletion type
- that it is enhancement type
- that it is n channel
- that it is p channel
- that electrons flow from D to S
- that holes flow from D to S
Windows is an operating system.
- Error may occur due to finite representation of numbers.
- Error may occur due to rounding.
- Error may occur due to finite representation of inherently infinite process.
Among the answer choices, the three options B, C and D can be inferred from the passage. But the main essence of the passage is that chemical agents are being used my military establishments in warfare which is not desirable. Therefore option C is the statement which best sums up the meaning of the passage.