Non Verbal Reasoning - Analytical Reasoning - Discussion
Discussion Forum : Analytical Reasoning - Section 1 (Q.No. 4)
4.
Find the number of triangles in the given figure.
Answer: Option
Explanation:
The figure may be labelled as shown.
The simplest triangles are AHB, GHI, BJC, GFE, GIE, IJE, CEJ and CDE i.e. 8 in number.
The triangles composed of two components each are HEG, BEC, HBE, JGE and ICE i.e. 5 in number.
The triangles composed of three components each are FHE, GCE and BED i.e. 3 in number.
There is only one triangle i.e. AGC composed of four components.
There is only one triangle i.e. AFD composed of nine components.
Thus, there are 8 + 5 + 3 + 1 + 1 = 18 triangles in the given figure.
Discussion:
32 comments Page 3 of 4.
Akter ali said:
7 years ago
The simple triangle means forming with 3 letters.
Two components forming with 4 letters.
Three components forming with 5 letters.
Two components forming with 4 letters.
Three components forming with 5 letters.
Swetha said:
1 decade ago
@Zarish Components refers to sides of the triangle.
Anonymus said:
8 years ago
The simplest triangles are AHB, GHI, BJC, GFE, GIE, IJE, CEJ and CDE which equals 8 in number.
The triangles composed of two components each are HEG, BEC, HBE, JGE and ICE = 5 in number.
The triangles composed of three components each are FHE, GCE and BED which are 3 in number.
There is only one triangle i.e. AGC composed of four components.
There is only one triangle i.e. AFD composed of nine components(sides of triangles.
Thus, there are 8 + 5 + 3 + 1 + 1 = 18 triangles in the given figure.
The triangles composed of two components each are HEG, BEC, HBE, JGE and ICE = 5 in number.
The triangles composed of three components each are FHE, GCE and BED which are 3 in number.
There is only one triangle i.e. AGC composed of four components.
There is only one triangle i.e. AFD composed of nine components(sides of triangles.
Thus, there are 8 + 5 + 3 + 1 + 1 = 18 triangles in the given figure.
Tejal ganatra said:
1 decade ago
Is there any trick to solve such problems?
Balaganesh akasapu said:
1 decade ago
Fortunately yes, we can use the concept of combinations to crack the problem with no time.
Cosu bardeskar said:
1 decade ago
Is there any trick to solve this type of problems.
Jitesh said:
9 years ago
Please anyone tell me the Short trick for solving the problem.
Jaisun said:
9 years ago
Will the formula is given above be applicable for all triangle based sums? Please tell me, I need help.
Karthik said:
9 years ago
How this way is possible?
No of nodes + 2 * No of inner nodes.
Ca anyone explain it?
No of nodes + 2 * No of inner nodes.
Ca anyone explain it?
Shashikant kumar said:
1 decade ago
The figure shows a triangle with many lines. If the number of internal lines from vertex E=4, and the number of internal lines parallel to base is 2, then [4 X 2 X (2+1)]/2 = 12 and then add the rest small triangle at side and the main large triangle, you will get 18.
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