Networking - Subnetting - Discussion
Discussion Forum : Subnetting - Subnetting (Q.No. 1)
1.
Your router has the following IP address on Ethernet0: 172.16.2.1/23. Which of the following can be valid host IDs on the LAN interface attached to the router?
- 172.16.1.100
- 172.16.1.198
- 172.16.2.255
- 172.16.3.0
Answer: Option
Explanation:
The router's IP address on the E0 interface is 172.16.2.1/23, which is 255.255.254.0. This makes the third octet a block size of 2. The router's interface is in the 2.0 subnet, and the broadcast address is 3.255 because the next subnet is 4.0. The valid host range is 2.1 through 3.254. The router is using the first valid host address in the range.
Discussion:
36 comments Page 3 of 4.
Santhosh said:
1 decade ago
The valid host id is from 172.16.2.0 to 172.16.3.254 [excluding 172.16.2.1(as this is itself routers id)].
And the broadcast add is 172.16.3.255.
And the broadcast add is 172.16.3.255.
Varun tyagi said:
1 decade ago
2 is the block size.
So 0, 2, 4, 6 is N.ID.
0.1, 0.2, 0.3 to 1.254 are host.
Similarly.
2.1, 2.2, 2.3, 2.4 to 2.254, 2.255, 3.1, 3.2 to 3.254 are host.
But 3.255 are B.id and 4.0 n.id.
So 0, 2, 4, 6 is N.ID.
0.1, 0.2, 0.3 to 1.254 are host.
Similarly.
2.1, 2.2, 2.3, 2.4 to 2.254, 2.255, 3.1, 3.2 to 3.254 are host.
But 3.255 are B.id and 4.0 n.id.
Gabe said:
1 decade ago
Don't know if it helps but 172.16.1.100 and 172.16.1.198 are kinda off from the default gateway 172.16.2.1/23 notice that to there?
Felix said:
1 decade ago
The valid host range will be (172.16,2.1-172.16.3.254).
The network address : 172.16.2.0.
The broadcast address: 172,16.3.255.
The network 172.16.2.0 will ends 172.16.2.55 then it will become 172.16.3.0 which is still on the range of the network.
The network address : 172.16.2.0.
The broadcast address: 172,16.3.255.
The network 172.16.2.0 will ends 172.16.2.55 then it will become 172.16.3.0 which is still on the range of the network.
Davit said:
1 decade ago
00000000.00000000.0000000|0.00000000.
76543210.76543210.7654321|0.76543210.
1.255.
IP starts from 2.1 and ends with 3.254. So we can't use these numbers. It means we can use 172.16.2.1 - 172.16.3.254. I think so:x.
76543210.76543210.7654321|0.76543210.
1.255.
IP starts from 2.1 and ends with 3.254. So we can't use these numbers. It means we can use 172.16.2.1 - 172.16.3.254. I think so:x.
Akira said:
10 years ago
Can you please explain this from the scratch?
Kapil said:
9 years ago
Can any one help me to understand subnetting?
Sundha said:
9 years ago
How it is. Can you explain me clearly?
Datta Ikhe said:
9 years ago
Answer C is correct because;
Given IP- 172.16.2.1/23.
First IP used as Network Id: 172.16.00000010.00000000(172.16.2.0).
First Valid Host IP: 172.16.00000011.00000000(172.16.3.0).
Broadcast IP: 172.16.3.255 & NOT 172.16.2.255.
So, 172.16.2.255 is a valid Host IP.
Given IP- 172.16.2.1/23.
First IP used as Network Id: 172.16.00000010.00000000(172.16.2.0).
First Valid Host IP: 172.16.00000011.00000000(172.16.3.0).
Broadcast IP: 172.16.3.255 & NOT 172.16.2.255.
So, 172.16.2.255 is a valid Host IP.
Shahnas said:
9 years ago
What means of /23?
Can we take it as subnet mask? and why we want to calculate 32-23=9?
Guys! can you tell me the in IP address and subnet mask of this?
Can we take it as subnet mask? and why we want to calculate 32-23=9?
Guys! can you tell me the in IP address and subnet mask of this?
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