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Networking - Subnetting - Discussion

Discussion Forum : Subnetting - Subnetting (Q.No. 13)
Subnetting
13.
You have a network with a subnet of 172.16.17.0/22. Which is the valid host address?
172.16.17.1 255.255.255.252
172.16.0.1 255.255.240.0
172.16.20.1 255.255.254.0
172.16.18.255 255.255.252.0
Answer: Option
Explanation:
A Class B network ID with a /22 mask is 255.255.252.0, with a block size of 4 in the third octet. The network address in the question is in subnet 172.16.16.0 with a broadcast address of 172.16.19.255. Only option E even has the correct subnet mask listed, and 172.16.18.255 is a valid host.
Discussion:
13 comments Page 2 of 2.
Abera said:   1 year ago
D is the correct answer in the case of /22 =255.255.252.0 but A not.
Subhankar said:   7 years ago
Please describe why A is not the correct answer?
K.madhusudan reddy said:   6 years ago
Can you give the proper explanation?
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