Networking - Subnetting - Discussion
Discussion Forum : Subnetting - Subnetting (Q.No. 7)
7.
If an Ethernet port on a router were assigned an IP address of 172.16.112.1/25, what would be the valid subnet address of this host?
Answer: Option
Explanation:
A /25 mask is 255.255.255.128. Used with a Class B network, the third and fourth octets are used for subnetting with a total of 9 subnet bits, 8 bits in the third octet and 1 bit in the fourth octet. Since there is only 1 bit in the fourth octet, the bit is either off or on-which is a value of 0 or 128. The host in the question is in the 0 subnet, which has a broadcast address of 127 since 128 is the next subnet.
Discussion:
14 comments Page 2 of 2.
Jimbo jones said:
9 years ago
I think the answer is 172.16.0.0 network. It's still a class b network so you can only touch the 3rd octet.
Amala said:
8 years ago
Then what's the no of networks and host per network?
Arnold Subhashnagar said:
5 years ago
@All.
It is said that it is a 1/25 so the valid IP address will fall only in this domain of having 24-bit octet containing the one extra bit as per the question.
It is said that it is a 1/25 so the valid IP address will fall only in this domain of having 24-bit octet containing the one extra bit as per the question.
Damy mgimba said:
5 years ago
I'm not understanding, anyone, can explain more?
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