Networking - Subnetting - Discussion
Discussion Forum : Subnetting - Subnetting (Q.No. 3)
3.
A network administrator is connecting hosts A and B directly through their Ethernet interfaces, as shown in the illustration. Ping attempts between the hosts are unsuccessful. What can be
done to provide connectivity between the hosts?
- A crossover cable should be used in place of the straight-through cable.
- A rollover cable should be used in place of the straight-through cable.
- The subnet masks should be set to 255.255.255.192.
- A default gateway needs to be set on each host.
- The subnet masks should be set to 255.255.255.0.
Answer: Option
Explanation:
First, if you have two hosts directly connected, as shown in the graphic, then you need
a crossover cable. A straight-through cable won't work. Second, the hosts have different
masks, which puts them in different subnets. The easy solution is just to set both masks to
255.255.255.0 (/24).
Discussion:
26 comments Page 3 of 3.
Yasser said:
1 decade ago
The .244 in mask means that there are only 4 allowable host bits thus can't afford to make address .201 for right host if all 4 bits where ones.
Mokonnin Alemu said:
1 decade ago
First, if you have two hosts directly connected, then you need a crossover cable. A straight-through cable won't work.
Second, the hosts have different masks, which puts them in different subnets. The easy solution is just to set both masks to 255.255.255.0 /24.
Second, the hosts have different masks, which puts them in different subnets. The easy solution is just to set both masks to 255.255.255.0 /24.
Derek mercado said:
1 decade ago
I too am confused as it seems they both have the same subnet mask (x.x.x.240) while i agrees the they are different subnets eg .20 is in subnet .16 and .201 is in subnet .192 they clearly share the same subnet mask x.x.x.240 because it states it in the example and it states in the answer that the hosts have different subnet masks, maybe I am not understanding it correctly.
Daisy said:
1 decade ago
The series is as follows:
192.168.1.0, valid host(1 to 14).
192.168.1.16, valid host(17 to 30).
192.168.1.32, valid host.
.
.
.
.
192.168.1.192 (193 to 206).
192.168.1.208.
192.168.1.224 ().
192.168.1.240.. hence the given IP address of both host falls in different subnets.
192.168.1.0, valid host(1 to 14).
192.168.1.16, valid host(17 to 30).
192.168.1.32, valid host.
.
.
.
.
192.168.1.192 (193 to 206).
192.168.1.208.
192.168.1.224 ().
192.168.1.240.. hence the given IP address of both host falls in different subnets.
Alooma said:
1 decade ago
But looking at the mask address they are both on the same mask address 255.255.255.240, please explain.
Shivani Jain said:
1 decade ago
As AND operation of IP address and Subnet mask gives us the Network address. In this case network address is different with given subnet address.
But when subnet mask (255.255.255.0) is used same network address will obtained and hence both will be on same network.
But when subnet mask (255.255.255.0) is used same network address will obtained and hence both will be on same network.
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