Networking - Subnetting - Discussion

It was kind of confusing. But crossover cable should be used and IP add should be in a class C. There won't be any problem.

It was kind of confusing. But crossover cable should be used and IP add should be in a class C. There won't be any problem.

In this mask, Only 14 host address will be used.

20 comes between 16 to 31.

But 201 is not between 16 to 31.

So it is another subnet. Hence communication is possible. And cause of cable as will.

Suppose a company ABC wants to develop two LANs for its different departments in the same building. For LAN network the main factors to consider are reliability, security, and speed. The company has also no cost constraints for the development of LANs.

After LAN development, this company also needs to connect these two LANs with each other and with its remote offices located in different cities.

1. Identify the suitable medium that will fulfill the requirements of the company in order to develop LANs.

2. Which type of address will be associated when data will travel from one user to another user within same LAN?
VLAN. if two people attempt to send information at the same time,

3. If the user of one LAN wants to communicate, with a remote user located in another city network then which type of address will be used?

4. Which type of networking device will be used to transfer data from one of the LANs to a remote user located in the network of another city?

Please tell me the solution.

D answer is perfect. You check again. It is a private IP address.

Please give a little explanation about crossover cable theory.

We cannot use subnet mask 255.255.255.240 with both IP addresses as this subnet mask will take them in two different subnets(networks).

The binary equivalent of 240 is 11110000. i.e 16 is the increment.

The possible networks are:

192.168.1.0 to 192.168.1.15.
192.168.1.16 to 192.168.1.31------>192.168.1.20 belongs to here.
.
.
.
.
.
192.168.1.192 to 192.168.1.207----->192.168.1.201 belongs here.
192.168.1.208 to 192.168.1.223.
192.168.1.224.

So we can clearly see that if we use subnet mask 255.255.255.240 then communication will not be possible as both will be on separate networks. So we have to use 255.255.255.0 subnet in both so that they belong to same network.

Please explain why?

The .244 in mask means that there are only 4 allowable host bits thus can't afford to make address .201 for right host if all 4 bits where ones.

First, if you have two hosts directly connected, then you need a crossover cable. A straight-through cable won't work.

Second, the hosts have different masks, which puts them in different subnets. The easy solution is just to set both masks to 255.255.255.0 /24.