Networking - Subnetting - Discussion

Discussion Forum : Subnetting - Subnetting (Q.No. 11)
11.
You need to configure a server that is on the subnet 192.168.19.24/29. The router has the first available host address. Which of the following should you assign to the server?
192.168.19.0 255.255.255.0
192.168.19.33 255.255.255.240
192.168.19.26 255.255.255.248
192.168.19.31 255.255.255.248
Answer: Option
Explanation:
A /29 is 255.255.255.248, which is a block size of 8 in the fourth octet. The subnets are 0, 8, 16, 24, 32, 40, etc. 192.168.19.24 is the 24 subnet, and since 32 is the next subnet, the broadcast address for the 24 subnet is 31. 192.168.19.26 is the only correct answer.
Discussion:
15 comments Page 2 of 2.

Anonymous said:   8 years ago
The first host address should be:

Address: 192.168.19.25.
Subnet: 255.255.255.248.

Hari said:   2 months ago
Can we provide a broadcast IP address to a server?

Anyone, please clarify.

Nani said:   1 decade ago
How the block size is 8 in the fourth octet?

Vikas said:   8 years ago
I got this as the answer 192.168.19.23.

Inuya said:   2 years ago
D is the correct answer.


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