Networking - Subnetting - Discussion
Discussion Forum : Subnetting - Subnetting (Q.No. 10)
10.
The network address of 172.16.0.0/19 provides how many subnets and hosts?
Answer: Option
Explanation:
A CIDR address of /19 is 255.255.224.0. This is a Class B address, so that is only 3 subnet bits, but it provides 13 host bits, or 8 subnets, each with 8,190 hosts.
Discussion:
20 comments Page 2 of 2.
Abhishek said:
6 years ago
How to calculate the number of host and number of the network for said IP-134.141.7.11 and subnet is 255.255.255.0
Ganapathi said:
7 years ago
2^3 = 8 subnet.
2^13 -2= 8190 hosts each only Host need public IP & broadcast IP. Subnet don't need -2.
2^13 -2= 8190 hosts each only Host need public IP & broadcast IP. Subnet don't need -2.
Mehedi hasan said:
10 years ago
Answer is wrong, the correct answer will be 16128 and useable host: 16126 but the subnet is ok.
Kalimullah Ahmadzai said:
1 decade ago
@Vikas Beniwal and @Vasil are right. we don't need to subtract from the network portion.
Daniel said:
3 years ago
32 subnet and 8192 hosts. It's class b the values of third octet is 32.
Davil said:
10 years ago
Wrong answer. 2 power 5 is number of host per subnet.
Gaddo OroMan said:
2 years ago
I agree with you, Thanks @James willie.
(1)
Harshit said:
6 years ago
I can't understand it, Please explain.
(1)
Pragati said:
1 decade ago
How to calculate number of hosts?
Dede said:
8 years ago
I agree @Gajulapalli Naveen.
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