Networking - Subnetting - Discussion
Discussion Forum : Subnetting - Subnetting (Q.No. 4)
4.
What is the maximum number of IP addresses that can be assigned to hosts on a local subnet that uses the 255.255.255.224 subnet mask?
Answer: Option
Explanation:
A /27 (255.255.255.224) is 3 bits on and 5 bits off. This provides 8 subnets, each with 30 hosts. Does it matter if this mask is used with a Class A, B, or C network address? Not at all. The number of host bits would never change.
Discussion:
23 comments Page 2 of 3.
Nishu Kumar said:
8 years ago
(1)255.255.255.224
128+64+32=224.
2^3 =8, 2^5-2= 32 -2 =30
(2) formula;
Block size = 256 - Actual subnet mask,
=256 -224,
= 32.
128+64+32=224.
2^3 =8, 2^5-2= 32 -2 =30
(2) formula;
Block size = 256 - Actual subnet mask,
=256 -224,
= 32.
Tara said:
8 years ago
@Seonti.
Here the question is 255.255.255.224.
Convert to binary it is 11111111 11111111 11111111 11100000.
Count nos of 1 ...it is 27.
Here the question is 255.255.255.224.
Convert to binary it is 11111111 11111111 11111111 11100000.
Count nos of 1 ...it is 27.
Bijay KC said:
8 years ago
Thank you @Nikhil.
Ankit Chaturvedi said:
8 years ago
Total host= 2^( use off bits) - 2.
Nikita said:
6 years ago
Thank you all for explaining it.
(1)
Melin said:
6 years ago
Thanks for the explanation.
(1)
Neha said:
5 years ago
Thanks all.
(1)
Jayden said:
4 years ago
255.255.255.224 convert to binary:
11111111.11111111.11111111.11100000 = /27 bits, 5 bits left for hosts,
subnet-mask has 32, therefore 32 - 27 = 5,
2^5 - 2 = 32 - 2 = 30.
11111111.11111111.11111111.11100000 = /27 bits, 5 bits left for hosts,
subnet-mask has 32, therefore 32 - 27 = 5,
2^5 - 2 = 32 - 2 = 30.
(23)
Aditya said:
4 years ago
The default subnet mask of class C address we have to remember 255.255.
(1)
Aditya said:
4 years ago
255.255.255.0 default class C subnet mask.
(2)
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