Networking - Networking Basics - Discussion
Discussion Forum : Networking Basics - Networking Basics (Q.No. 7)
7.
Which of the following is the valid host range for the subnet on which the IP address 192.168.168.188 255.255.255.192 resides?
Answer: Option
Explanation:
256 - 192 = 64. 64 + 64 = 128. 128 + 64 = 192. The subnet is 128, the broadcast address
is 191, and the valid host range is the numbers in between, or 129-190.
Discussion:
46 comments Page 5 of 5.
Lavanya S S said:
1 decade ago
Here the subnet mask is 255.255.255.192 means only the last value is changing so subtract it from 255, you will get 64 means out of 255 IP's 64 is already used only 192 IP's are available.
256/4=64 means 0-63, 64-127, 128-191, 192-255 all 4 segments contains 64 IP's, out of which one segment is already used (lets not worry about it).
Now check the IP given which is 192. 168. 168. 188 which falls in the range 128-191 so here the valid host range will be from 129-190 because first one is always network IP, the last one is always the broadcast IP.
256/4=64 means 0-63, 64-127, 128-191, 192-255 all 4 segments contains 64 IP's, out of which one segment is already used (lets not worry about it).
Now check the IP given which is 192. 168. 168. 188 which falls in the range 128-191 so here the valid host range will be from 129-190 because first one is always network IP, the last one is always the broadcast IP.
SandeepYadav said:
1 decade ago
This value is right not wrong.
First of all we need to be the see the address and now.
We take broadcast address 256 then in this we subtract the value of last gourd subnet mask (192). Then we add the same bit of subtracting then we find the 128 also and then we re add the value (64) then we find out the 192 this will be the broadcast address of segment.
First of all we need to be the see the address and now.
We take broadcast address 256 then in this we subtract the value of last gourd subnet mask (192). Then we add the same bit of subtracting then we find the 128 also and then we re add the value (64) then we find out the 192 this will be the broadcast address of segment.
Rohini said:
1 decade ago
Why the value should be between 129 and 191. It should be between 128-191. Also why the broadcast address is 191?
Dinesh Rathinam said:
1 decade ago
Actually the value given is wrong. the value should be 192.168.168.128
then only we can get the correct value.
192-128=64
so that we can get 64 values.that valid host range value should be between 129 to 191.
i think correct answer is B.
does anybody refuse it....?
then only we can get the correct value.
192-128=64
so that we can get 64 values.that valid host range value should be between 129 to 191.
i think correct answer is B.
does anybody refuse it....?
Shahnawaz said:
1 decade ago
I didn't understand. Can anyone explain me clearly please?
Guru said:
1 decade ago
I didn't understand, please. Can anyone explain clearly.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers