Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 1 (Q.No. 5)
5.
There is a loss of heat in an irreversible process.
Discussion:
40 comments Page 2 of 4.
Praveen S said:
9 years ago
The isentropic process is a reversible adiabatic process.
In an reversible process pressure remains unchanged.
In adiabatic process there is no heat transfer between the system and the surroundings.
In an reversible process pressure remains unchanged.
In adiabatic process there is no heat transfer between the system and the surroundings.
Gaurav said:
10 years ago
(1) For example heat lose b/w body a 500 k and body b 1000 k.
(2) Heat lose b/w body c 300 k and body d 500 k. So process 1 more irreversible then process 2.
(3) For ex heat lose b/w body h 500 k and body I 499.999 k temperature.
Here process 3 is reversible because process is very slow.
So in this question both answer is possible.
(2) Heat lose b/w body c 300 k and body d 500 k. So process 1 more irreversible then process 2.
(3) For ex heat lose b/w body h 500 k and body I 499.999 k temperature.
Here process 3 is reversible because process is very slow.
So in this question both answer is possible.
Gaurav said:
10 years ago
In this if temperature difference is very negligible between two bodies then heat lose very slow and process become reversible. But in these bodies having considerable temperature difference then heat lose become fast and process become irreversible. So in these case both answer is possible.
Sumit said:
1 decade ago
There is no loss of heat but available energy in irreversible process.
Prashant raturi said:
1 decade ago
Hello friends.
The correct answer is FALSE,
CHANGE IN ENTROPY OF SYSTEM = INT(DQ/T)+ENTROPY GENERATION;
For irreversible process change in entropy will be greater than 0, and as we know that entropy generation is always +,
And for no heat loss the quantity int (dq/T) will be 0 but due to entropy generation change will be +.
The correct answer is FALSE,
CHANGE IN ENTROPY OF SYSTEM = INT(DQ/T)+ENTROPY GENERATION;
For irreversible process change in entropy will be greater than 0, and as we know that entropy generation is always +,
And for no heat loss the quantity int (dq/T) will be 0 but due to entropy generation change will be +.
Nagu said:
1 decade ago
In irreversible process some losses will takes places for example man walk in forward direction is easy but in reverse direction little difficult.
Ankit Singh said:
1 decade ago
It's a contradictory question. Both answer is possible.
Let's take an example. A gas chamber is subdivided by partition and suddenly partition is removed and it is insulated. It's example of irreversibly but more closet answer is option A.
Let's take an example. A gas chamber is subdivided by partition and suddenly partition is removed and it is insulated. It's example of irreversibly but more closet answer is option A.
ROHIT KUMAR said:
1 decade ago
In irreversible process, there is a loss of heat due to friction, radiation, or conduction.
Biswaranjan Biswal said:
1 decade ago
A process is said to be irreversible when it doesn't come back to its original state. So their must be some energy losses and heat is also a form of energy.
Devan said:
1 decade ago
Due to entropy generation.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers