Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 2 (Q.No. 13)
13.
The entropy of water at 0°C is assumed to be
Discussion:
27 comments Page 2 of 3.
Shekhar said:
9 years ago
I think it should be 0 kelvin.
Thomas said:
9 years ago
Entropy is always greater than zero for all temp greater than 0K.
Shubham said:
9 years ago
It's wrong que actually entropy is zero at absolute zero temperature (0 k).
Santosh kumar said:
9 years ago
Yeah, it's wrong answer S = 0 at -273.15 degree C.
Kishan said:
8 years ago
According to 3rd law of thermodynamics entropy is =0 at 0 kelvin, not at 0-degree celcius.
Sweta said:
8 years ago
Obviously, it is 0K as at this temperature the molecular momentum is zero. Even during calculation, we don't use celsius.
Some of you said q=0.
How is q=0 as we have still latent heat of vapourisation?
Some of you said q=0.
How is q=0 as we have still latent heat of vapourisation?
Mr. Singh said:
8 years ago
Entropy is zero at absolute zero temperature. Absolute zero temperature = 0K.
Akash said:
8 years ago
When 0k Entropy is 0 but it only applicable for pure crystal substance so water is not pure Crystalline substance.
Muhammed aslam said:
8 years ago
Actually, entropy has some value at 0 degree centigarade. We cannot achieve zero entropy (according to 3rd law). But for ease of calculation we assume entropy is zero for water at zero degree celcius. Steam table is based on this concept. However absolute value of entropy or enthalpy is not important at all. Always we consider change in entropy on process.
Ananda said:
8 years ago
S=mcln(t2/t1).
Here t1=t2=273 kelvin,
So ln(273/273)=ln(1)= 0,
Hence S=0.
Here t1=t2=273 kelvin,
So ln(273/273)=ln(1)= 0,
Hence S=0.
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