Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 2 (Q.No. 19)
19.
The free expansion process is a constant enthalpy process.
Discussion:
13 comments Page 2 of 2.
Sreeju said:
1 decade ago
dH = dE+pdV.
In free expansion, the external work(pdV) is obtained from the internal energy of the system. In ideal condition the change in the internal energy and the pdV work is equal and opposite in sign(pdV=-dE).
So, dH=0. Enthalpy constant.
In free expansion, the external work(pdV) is obtained from the internal energy of the system. In ideal condition the change in the internal energy and the pdV work is equal and opposite in sign(pdV=-dE).
So, dH=0. Enthalpy constant.
Rohit singh said:
1 decade ago
Free expansion is an irreversible process in it both internal energy and enthalpy remains constant.
Vikash said:
1 decade ago
In free expansion internal energy remains constant not enthalpy.
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